Question : Simplify.
$\cos \left(36^{\circ}-\mathrm{A}\right) \cos \left(36^{\circ}+\mathrm{A}\right)+\cos \left(54^{\circ}-\mathrm{A}\right) \cos \left(54^{\circ}+\mathrm{A}\right)$
Option 1: $\cos A$
Option 2: $\sin 2A$
Option 3: $\cos 2A$
Option 4: $\sin A$
Correct Answer: $\cos 2A$
Solution :
Given: $\cos(36^{\circ}-A) \cos (36^{\circ}+A)+\cos (54^{\circ}-A) \cos (54^{\circ}+A)$
= $\sin[90^{\circ} - (36^{\circ} - A)]\sin[90^{\circ} - (36^{\circ} + A)] + \cos (54^\circ - A) \cos (54^\circ + A)$
= $\sin(54^\circ + A)\sin(54^\circ - A) + \cos (54^\circ - A)\cos (54^\circ + A)$
= $\cos(54^{\circ} + A - 54^{\circ} + A) = \cos2A$
Hence, the correct answer is $\cos2A$.
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