Question : Simplify the given expression.
$\frac{a^2-b^2-2 b c-c^2}{a^2+b^2+2 a b-c^2}$
Option 1: $\frac{a+b+c}{a-b-c}$
Option 2: $\frac{a-b-c}{a+b-c}$
Option 3: $\frac{a+b-c}{a-b-c}$
Option 4: $\frac{a-b+c}{a+b-c}$
Correct Answer: $\frac{a-b-c}{a+b-c}$
Solution :
Given: $\frac{a^2-b^2-2 b c-c^2}{a^2+b^2+2 a b-c^2}$
= $\frac{a^2-(b^2+2 b c+c^2)}{(a^2+b^2+2 a b)-c^2}$
= $\frac{a^2-(b+c)^2}{(a+b)^2-c^2}$
= $\frac{(a-b-c)(a+b+c)}{(a+b-c)(a+b+c)}$
= $\frac{a-b-c}{a+b-c}$
Hence, the correct answer is $\frac{a-b-c}{a+b-c}$.
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