Question : The value of $\left(\tan ^2 A+\cot ^2 A-2\right)-\sec ^2 A \operatorname{cosec}^2 A$ is:
Option 1: –4
Option 2: –1
Option 3: 1
Option 4: 4
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Correct Answer: –4
Solution :
$\left(\tan ^2 A+\cot ^2 A-2\right)-\sec ^2 A \operatorname{cosec}^2 A$
$=\left[(1+\tan ^2 A)+(1+\cot ^2 A)-4\right]-\sec ^2 A \operatorname{cosec}^2 A$
$=(\sec ^2 A+ \operatorname{cosec}^2 A-4)-\sec ^2 A \operatorname{cosec}^2 A$
$=(\frac{1}{\cos ^2 A}+\frac{1}{\sin ^2 A})-4-\sec ^2 A \operatorname{cosec}^2 A$
$=(\frac{\sin ^2 A+\cos ^2 A}{\sin ^2 A\cos ^2 A})-4-\sec ^2 A \operatorname{cosec}^2 A$
$=(\frac{1}{\sin ^2 A\cos ^2 A})-4-\sec ^2 A \operatorname{cosec}^2 A$
$=\sec ^2 A \operatorname{cosec}^2 A-4-\sec ^2 A \operatorname{cosec}^2 A$
$=-4$
Hence, the correct answer is –4.
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