Question : Two circles with diameters of 50 cm and 58 cm, respectively, intersect each other at points A and B, such that the length of the common chord is 40 cm. Find the distance (in cm) between the centres of these two circles.
Option 1: 34
Option 2: 37
Option 3: 36
Option 4: 35
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Correct Answer: 36
Solution :
Given: MA = $\frac{50}{2}$ = 25 cm, NA = $\frac{58}{2}$ = 29 cm and OA = OB = $\frac{40}{2}$ = 20 cm
From $\triangle$AMO,
OM = $\sqrt{25^2-20^2}=\sqrt{225}$ = 15 cm
Also from $\triangle$ANO,
ON = $\sqrt{29^2-20^2}=\sqrt{441}$ = 21 cm
So, the distance between the centres of these two circles = MN = OM + ON = 15 + 21 = 36 cm
Hence, the correct answer is 36.
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