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Bachelor of Medical Radiology & Imaging Technology (BMRIT) is a 4-year To enroll in BMRIT course, you must have passed class 12th in Science stream with at least 50% marks. Admission to the BMRIT course is based on merit only.

When it comes to what is a good score in SLAT 2026 for SLS Pune, a score of 45 to 50 marks can be termed as a good score. In the past some candidates have been shortlisted for PI rounds. However, admissions in SLS Pune are not guaranteed at this

The BBA LLB course is offered by most of the government and private law colleges in India. Some of the top law colleges in Maharashtra that offers BBA LLB course are

• Symbiosis Law College Pune
• ILS Pune
• MNLU Nagpur
• Bharati Vidyapeeth Pune
• New Law College Pune

Please check the list

To get admission into top Pharmacy colleges in Madhya Pradesh, students generally need to appear for CUET-UG (for B.Pharm in some universities) or state CETs (if applicable through the All India Quota). DTE, MP, conducts counselling for the pharmacy courses. For M.Pharm, candidates need to qualify GPAT , which is

Hi Prerana,

Typically the first semester exam (Odd semester) for BSc Zoology is held around November/ December. Refer to your college website for specific dates. Hope this helps.

Hi Anand satish Jagtap,
You can download the free pdf of MH CET Law prepartion guide.It is in English

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Hi, Ashutosh Kumar
Bihar Board Matric ka admit card jari ho gaya hai. matric admit card download karne ka link official website https://exam.biharboardonline.org/ per active hai, lekin ise school login se hi download kiya ja sakta hai, aur jankari ke liye ye lekh dekhe; https://school.careers360.com/hi/articles/bihar-board-10th-admit-card

HI Manisha Maharana

You can download the JEE Mains 10 Free Mock Test with Detailed solutions. Its a feely downloadable pdf.
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Hi, you can apply for admissions in Nirma University, NFSU Ahemdabad, Alliance, IPU University and affiliated instiutes (in case you are reserved category candidates), UPES Dehradun, BITS Law School etc.

A general equation of a circle is

$
x^2+y^2+2 g x+2 f y+c=0
$

Since it passes through $(0,0)$,

$
c=0
$

So the equation becomes

$
x^2+y^2+2 g x+2 f y=0
$

It cuts the x -axis at ( $a, 0$ ).

Substituting:

$
a^2+2 g a=0
$

g=-a/2