Hello student,

Considering the previous year cut off rank list for RVCE through KCET, the minimum rank required for admission in RVCE through KCET under ST category is listed as follows:

·         403 for Computer Science and Engineering

·         7058 for Information Science & Engineering

·         2364 for Electronics &

Admission through kcet in BMS College of Engineering  consult 7676O8OOO8 

contact me for admission guidance 9337934752(call/whatsapp)

dear aspirant,

There is no such thing as Subject Wise Cutoff In JEE Main 2018. Candidates need not worry about passing eachsubject separately. They just need to score enough out of the total of 3 subjects together in admission in the IITs, NITs, IIITs, and GFTIs.And candidates should have secured

Contact me for admission guidance 9337934752(call/whatsapp)

Yes. This year there are chances of getting Kumaraguru college, Coimbatore through TNEA for your cut off mark. 

Dear Candidate

In that case you must as soon as possible contact the person in charge stating your query.

Do not Delay.

Your name should not have been missed. 

Give your personal details in the mail like roll no, name, address.

At this stage, I will suggest you must use

Hi.

You can check the cut-off for JEE Mains 2019 and previous years using the link given below :-

Also don't forget to remember that you should have got atleast 75% marks in your class 12 Board examination or in top 20 percentile of that exam to get the admission

Hello Gangadhar !!

Maharashtra has not released the cut off list yet .

Last year the cut off for OBC for BJMC under 30% state quota was 545. Whereas for 70% regional quota it was 505.

This year the cut offs will be increased by at least 20-30 marks .

IPU is no longer taking CET for law 2019. Admission will be based on CLAT score for BA/BBA LLB program. Counselling may start from 18th june to 1st augest then after ipu will release their merit list.