BITS Pilani- Hyderabad Campus, Hyderabad
Hi Rudra Viroja,
Admission to B.Tech programs at BITS Pilani Hyderabad, including those for students with a diploma, is primarily through BITSAT i.e. BITS Admission Test. There is no direct lateral entry into the second year for diploma holders. Candidates must qualify in BITSAT and meet the minimum eligibility criteria,
Here is the detailed admission process,
Candidates seeking admission shall first check the course-specific eligibility criteria. Eligible students can further fill out the application form for the respective course/or the required examination.
BITS Hyderabad offers admission to BTech/BE/BPharm/MSc courses is based on merit in BITSAT [BITS Admission test]. Candidates qualifying
Hello aspirant,
Students at BITS Hyderabad can choose from a variety of curricula and receive attractive packages for employment in reputable companies. The placement process at BITS Hyderabad begins with the institute sending out invitations to firms for the placement drive, and the companies then choose individuals based on their
Question : The value of $\frac{4 \tan ^2 30^{\circ}+\sin ^2 30^{\circ} \cos ^2 45^{\circ}+\sec ^2 48^{\circ}-\cot ^2 42^{\circ}}{\cos 37^{\circ} \sin 53^{\circ}+\sin 37^{\circ} \cos 53^{\circ}+\tan 18^{\circ} \tan 72^{\circ}}$ is:
Option 1: $\frac{35}{48}$
Option 2: $\frac{59}{48}$
Option 3: $\frac{49}{24}$
Option 4: $\frac{35}{24}$
Correct Answer: $\frac{59}{48}$
Solution : Given: $\frac{4 \tan ^2 30^{\circ}+\sin ^2 30^{\circ} \cos ^2 45^{\circ}+\sec ^2 48^{\circ}-\cot ^2 42^{\circ}}{\cos 37^{\circ} \sin 53^{\circ}+\sin 37^{\circ} \cos 53^{\circ}+\tan 18^{\circ} \tan 72^{\circ}}$ We know that $\tan 30^{\circ} = \frac{1}{\sqrt{3}}$ $\sin 30^{\circ} = \frac{1}{2}$ $\cos 45^{\circ} = \frac{1}{\sqrt{2}}$ $\cos 37^{\circ} = \cos (90^{\circ} - 53^{\circ})
The Goa Board HSSC 2023 syllabus is essential for students studying for their class 12 exams since it contains the topics and units they must cover. Knowing the www.gbshse.gov.in curriculum 2023–24 would enable them to streamline their preparation process. The 'Study Material' section of gbshse.info will provide the
Hello,
I would suggest you to refer to the link below to check the fee structure-
http://www.bitsadmission.com/fdmain.aspx#feeschedule
Good luck!
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Hello Naaz,
No, you cannot get admission to BITS directly. The direct admission procedure is for the board toppers. Others have to take up the BITSAT Exam.
ELIGIBILITY CRITERIA:
Passed 10+2 examination from a recognised board with at least 60% in aggregate and must have studied Physics, Chemistry and Mathematics
Hello Raghvendra,
The cutoff of all the three campuses of BITS are as follows:
PILANI CAMPUS CUTOFF:
BE Chemical Engineering- 281
BE Civil Engineering- 269
BE Computer Science Engineering- 383
BE Electrical and Electronics Engineering- 341
BE Electronics and Instrumentation Engineering- 328
BE Manufacturing Engineering- 255
BE Mechanical Engineering- 313
If you are enquiring about Birla Institute of Science and Technology Hyderabad campus then here is the cut off for BITSAT 2020 to get admission in to BITS, Hyderabad
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