Christ University, Bangalore
Hello Aspirant,
Hope you are doing good.
As per your question, the SC opening rank for VNIT Nagpur for the CSE course is 5327 and the closing rank is 5400. This is for the male students. If you need any information regarding the cutoffs you can go through the following link: https://engineering.careers360.com/articles/jee-main-cutoff-for-vnit-nagpur
Remember that, cutoffs will depend upon various factors such as, difficulty level of the exam, number of students who have written the exam etc.,.
Hope this helps!!
Hey,
The highest salary package is about 14LPA and the average is about 6.5LPA for BCA in Christ University, Bangalore.
Please visit for detailed information about placements and packages at Chrit University here at : https://www.careers360.com/university/christ-university-bangalore/bca-course
Hope this helps you. Thank you.
Hello,
Yes, Christ University Bangalore will accept your APOSS( Andhra Pradesh Open School Society) certificate don't worry as any Government recognized board is accepted and APOSS( Andhra Pradesh Open School Society) is a government recognized board.
Hope this helps you,
Thank you
Question : Directions: In the following question, select the related number from the given alternatives. 7 : 32 :: 35 : ?
Option 1: 144
Option 2: 156
Option 3: 160
Option 4: 172
Correct Answer: 172
Solution : Given: 7 : 32 :: 35 : ?
Like, 7 : 32→(7 × 5) – 3 = 35 – 3 = 32 Similarly, for 35 : ?→(35 × 5) – 3 = 175 – 3 = 172
So, 35 is related to 172. Hence, the fourth option is correct.
Question : Directions: Select the option related to the third term in the same way as the second term is related to the first term and the sixth term is related to the fifth term. 273 : 21 :: 221 : ? :: 364 : 28
Option 1: 12
Option 2: 20
Option 3: 26
Option 4: 17
Correct Answer: 17
Solution : Given: 273 : 21 :: 221 : ? :: 364 : 28
Divide the first number by 13, to get the second number – Like, 273 : 21→273 ÷ 13 = 21 And, 364 : 28→364 ÷ 13 = 28 Similarly, follow the same pattern for 221 : ?→221 ÷ 13 = 17
So, 17 is related to 221. Hence, the fourth option is correct.
Hello aspirant,
The Central University Entrance Exam (CUET) is the entrance exam for Christ University. Since the entrance exam's name was changed from Central Universities Common Entrance Test (CUCET) to Central University Entrance Test (CUET), CUET and CUCET are the same. But Christ University doesn't give admission solely on the basis of CUET. It also conduct pi round.
Hope this information helps you.
Question : Select the correct passive form of the given sentence. They are lifting the car with a crane.
Option 1: The car was being lifted with a crane.
Option 2: The car is being lifted with a crane.
Option 3: The car had lifted with a crane.
Option 4: The car is lifted with a crane.
Correct Answer: The car is being lifted with a crane.
Solution : The correct choice is the second option.
Passive voice is the voice in which the object experiences an action rather than the person who performs the action. Hence, the object in the active sentence becomes the subject in the passive voice.
The structure of the passive sentence in the case of the present continuous tense is: "Object + is + being + past participle form of the main verb + prepositional phrase."
So, the correct sentence would be: "The car is being lifted with a crane."
Question : If $\tan A-\tan B-\tan C=\tan A \tan B \tan C$, what is the value of A in terms of B and C?
Option 1: $A = B + C$
Option 2: $A = 2 B - 2C$
Option 3: $A = B - C$
Option 4: $A=\frac{B-C}{2}$
Correct Answer: $A = B + C$
Solution : Given, $\tan A-\tan B-\tan C=\tan A \tan B \tan C$ ⇒ $\tan A - \tan A \tan B \tan C = \tan B + \tan C$ ⇒ $\tan A(1-\tan B \tan C)= \tan B + \tan C$ ⇒ $\tan A = \frac{\tan B + \tan C}{1-\tan B \tan C}$ ⇒ $\tan A = \tan(B+C)$ $\therefore A = B + C$ Hence, the correct answer is $A = B + C$.
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