Exam
Yes as per the Information Bulletin by NTA. Senior Secondary School Examination conducted by the National Institute of Open Schooling with a minimum of five subjects. will be eligible to write an exam for JEE Mains. But to sit for JEE Advanced exam, only top 2.5 lakhs students will get
Question : If $xy(x+y)=m$, then the value of $(x^3+y^3+3m)$ is:
Option 1: $\frac{m^3}{xy}$
Option 2: $\frac{m^3}{(x+y)^3}$
Option 3: $\frac{m^3}{x^3y^3}$
Option 4: $mx^3y^3$
Correct Answer: $\frac{m^3}{x^3y^3}$
Solution : Given: $xy(x+y)=m$ We know that the algebraic identity is $(x+y)^3=x^3+y^3+3xy(x+y)$. $xy(x+y)=m$ ⇒ $(x+y)=\frac{m}{xy}$ Take the cube on both sides of the above equation, we get, $(x+y)^3=(\frac{m}{xy})^3$ ⇒ $x^3+y^3+3xy(x+y)=\frac{m^3}{x^3y^3}$ Substitute the value of $xy(x+y)=m$ in above equation, we get, $x^3+y^3+3m=\frac{m^3}{x^3y^3}$ Hence, the correct answer is $\frac{m^3}{x^3y^3}$.
Question : Direction: A paper is folded and cut as shown below. How will it appear when unfolded?
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : When the paper is unfolded, the following figures will be obtained–
Hence, the second option is correct.
Question : Case Study: ABC Retail Chain (Continued)
The next step ABC Retail Chain should take after evaluating alternative courses of action is:
Option 1: Selecting an alternative
Option 2: Developing premises
Option 3: Setting objectives and goals
Option 4: Allocating resources
Correct Answer: Selecting an alternative
Solution : The correct answer is (a). Selecting an alternative
Once ABC Retail Chain has evaluated the various courses of action, the next logical step is to select the most appropriate alternative based on the evaluation criteria. This involves making a decision and choosing the
Question : If $\sec A=\frac{17}{15}$, then what is the value of $\cot A$?
Option 1: $\frac{15}{21}$
Option 2: $\frac{15}{7}$
Option 3: $\frac{8}{15}$
Option 4: $\frac{15}{8}$
Correct Answer: $\frac{15}{8}$
Solution : Given: $\sec A=\frac{17}{15}$ $⇒\cos A = \frac{15}{17}$ $⇒\sin A = \sqrt{1-\cos^2 A}= \sqrt{1-(\frac{15}{17})^2}$ = $\sqrt{\frac{64}{289}}$ = $\frac{8}{17}$ $\therefore \cot A = \frac{\cos A}{\sin A} = \frac{\frac{15}{17}}{\frac{8}{17}} = \frac{15}{8}$ Hence, the correct answer is $\frac{15}{8}$.
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