Correct Answer: $\frac{m^3}{x^3y^3}$

Solution : Given: $xy(x+y)=m$
We know that the algebraic identity is $(x+y)^3=x^3+y^3+3xy(x+y)$.
$xy(x+y)=m$
⇒ $(x+y)=\frac{m}{xy}$
Take the cube on both sides of the above equation, we get,
$(x+y)^3=(\frac{m}{xy})^3$
⇒ $x^3+y^3+3xy(x+y)=\frac{m^3}{x^3y^3}$
Substitute the value of $xy(x+y)=m$ in above equation, we get,
$x^3+y^3+3m=\frac{m^3}{x^3y^3}$
Hence, the correct answer is $\frac{m^3}{x^3y^3}$.

Correct Answer:

Solution : When the paper is unfolded, the following figures will be obtained–

Hence, the second option is correct.

Correct Answer: Selecting an alternative
  

Solution : The correct answer is (a). Selecting an alternative

Once ABC Retail Chain has evaluated the various courses of action, the next logical step is to select the most appropriate alternative based on the evaluation criteria. This involves making a decision and choosing the

Correct Answer: $\frac{15}{8}$

Solution : Given: $\sec A=\frac{17}{15}$
$⇒\cos A = \frac{15}{17}$
$⇒\sin A = \sqrt{1-\cos^2 A}= \sqrt{1-(\frac{15}{17})^2}$ = $\sqrt{\frac{64}{289}}$ = $\frac{8}{17}$
$\therefore \cot A = \frac{\cos A}{\sin A} = \frac{\frac{15}{17}}{\frac{8}{17}} = \frac{15}{8}$
Hence, the correct answer is $\frac{15}{8}$.

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The IPU CET online application form was released on February 1, 2024 and students can apply for IPU CET online till March 31, 2024 . The IPU CET application form 2024 will remain available to candidates seeking admission until May 31,

Correct Answer: 758897

Solution : Given:
NUMBER is written as 156897 and BARREN is written as 847791.

On combining the letters of both the given words, the codes for each letter are –
Like, NUMBER is written as 156897; N→1; U→5; M→6; B→8; E→9; R→7
And, BARREN is written as

Hello,

Since you are overall pass, you are not required to give compartment exam. CBSE provides you the option to give compartment to improve your score. If you are comfortable with having a failed subject in your marksheet, then you can skip it as you are overall pass.

However, it