Hello Ranjita,

The admission process for IIIT Hyderabad is on the basis of entrance exams like -

The admission authorities is conducting admissions to B.Tech programmes through channels like JEE main, Undergraduate Engineering Entrance Examination - UGEE– CSD/ ECD/ CND/ CLD/ NK/ NTSE or KVPY, Olympiad, Direct Admissions for Students

As per last year cut off you should get a minimum of 99.9 percentile so as to get CSE in IIIT Hyderabad .

Hello!

Every year cut off score for IIIT Hyderabad's of every branch is around 250-260, which means a rank around 1 thousand. Which mean you need to score a rank below 500 to get a seat in IIT Hyderabad!

So you need at least 99 percentile to be even eligible

Hello,

as per ranking NIT comes first after IIT and IIIT comes after BITs which is a private institute.

Performance of NIT:-

It is world class. NIT warangal is ranked 26 by NIRF and one of the top 5 NIT campus. placement of the campus is alomost done by big

Anwar, the registration for UGEE for admission in IIIT Hyderabad has not started yet. The notification will be released in the first week of February tentatively, after which the registration will start. The exam will be held by the end of April 2020 tentatively.

The registration will be done in

Hi Bhanu,

There are no management quota seats available in the IIIT Hyderabad campus as this college is one of the best college in India.They only take admission on the basis of score of JEE Mains and then they took interview,If you could make it to the interview then only

Hello!

The admission process of IIIT - H will start soon . You should keep an eye on their official website .

Modes of UG ADMISSION:

1. Though Olympiad / KVPY (For dual degree program admission in CSD , CND , CLD )
2. Direct admission for student abroad
3. JEE MAINS score

Yogesh, there is no IT branch in IIIT Hyderabad for BTech. It offers only two branches- CSE and ECE.

Now, the cutoff percentile for admission in CSE was 99.958238 after round 1 and 99.9187734 after round 2 of counselling for IIIT Hyderabad.

For ECE, the cutoff percentile was 99.929344 after

Amritha, you can calculate your approximate rank for JEE Mains using your percentile through the following formula:

(100-your total percentile) x 869010/100

So with 98.93 percentile, your rank would be around 9298.

Also, if the number of students increases to 12 lakh in the April session, the formula for rank