Staff Selection Commission Combined Graduate Level Exam
Question : A sum of INR 50,250 is divided into two parts such that the simple interest on the first part for $7 \frac{1}{2}$ years at $8 \frac{1}{3} \%$ p.a. is $\frac{5}{2}$ times the simple interest on the second part for $5 \frac{1}{4}$ years at $8 \%$ p.a. What is the difference (in INR ) between the two parts?
Option 1: 10,275
Option 2: 12,750
Option 3: 12,570
Option 4: 15,270
Correct Answer: 12,750
Solution : Let the 1st part be $100x$ and the 2nd part be $100y$. According to the question, $\frac{100x \times \frac{15}{2} \times \frac{25}{3}}{100} = \frac{5}{2} \times \frac{100y \times \frac{21}{4} \times 8}{100}$ ⇒ $2 \times 62.5x = 5 \times 42y$ ⇒ $25x = 42y$ Ratio of $x :
Question : Webbed neck is a characteristic of
Option 1: Down's syndrome
Option 2: Turner's syndrome
Option 3: Klinefelter's syndrome
Option 4: Cri-du-chat syndrome
Correct Answer: Turner's syndrome
Solution : The correct option is Turner's syndrome.
A webbed neck is a characteristic linked with the genetic disorder Turner syndrome. Turner syndrome is a female-only chromosomal condition in which one of the X chromosomes is partly or totally absent. Other distinguishing characteristics include small height,
Question : Directions: The sum of the present age of the father and his son is 60 years. Six years ago, the father's age was five times the age of the son. After 6 years, what will be the son's age?
Option 1: 45
Option 2: 25
Option 3: 20
Option 4: 33
Correct Answer: 20
Solution : Let the father's present age be A, and his son's present age be B.
As per the given information, The sum of the father's present age and his son's present age is 60 years ⇒ A + B = 60
6 years ago, the father's
Question : Two circles of radius 13 cm and 15 cm intersect each other at points A and B. If the length of the common chord is 24 cm, then what is the distance between their centres?
Option 1: 12 cm
Option 2: 16 cm
Option 3: 14 cm
Option 4: 18 cm
Correct Answer: 14 cm
Solution : Given: Two circles of radius 13 cm and 15 cm with centres O and P intersect at A and B. OP is the distance between the centres of circles. AB intersects OP at Q. AB = 24 cm AQ = BQ= $\frac{24}{2}$ = 12
Question : Direction: One statement is given following by two Assumptions I and II. You have to consider the statement to be true, even if it seems to be at variance from commonly known facts. You have to decide which of the given conclusions can be definitely be drawn from the given statement. Indicate your answer.
Statement: The rich must live more simply. All poor people are simple.
Conclusions:
I. Rich people waste money.
II. Poor people save money.
Option 1: Only I follows.
Option 2: Only II follows.
Option 3: Neither I nor II follows.
Option 4: Both I and II follows.
Correct Answer: Only I follows.
Solution : Given:
Statement:
The rich must live more simply. All poor people are simple.
The given statement states that the rich must live more simply. From this, it can be concluded that rich people waste money and they should not waste money and must
Question : If (a + b)2 = 100 and (a – b) = 4 then ab equals to:
Option 1: 116
Option 2: 84
Option 3: 21
Option 4: 53
Correct Answer: 21
Solution : (a + b)2 = 100 ⇒ a + b = 10 ............. (I) Also, a – b = 4 ................. (II) Adding (I) and (II) ⇒ 2a = 14 ⇒ a = 7 Put a = 7 in (I) ⇒ 7 + b =
Question : Direction: In this question, a word is represented by only one set of numbers as given in any one of the alternatives. The sets of numbers given in the alternatives are represented by two classes of alphabets as in the two matrices, given below. The columns and rows of Matrix (I) are numbered from 0 to 4 and that of Matrix (II) are numbered from 5 to 9. A letter from these matrices can be represented first by its row and next by its column, e.g. 'D' can be represented by 02,10, etc., and 'R' can be represented by 55, 67, etc. Similarly, you have to identify the set for the word.
'BEAR'
Option 1: 13, 11, 12, 78
Option 2: 31, 22, 23, 97
Option 3: 42, 34, 42, 79
Option 4: 24, 40, 23, 67
Correct Answer: 24, 40, 23, 67
Solution : Given: BEAR
Number representations of each letter: B → 00, 31, 42, 13, 24 E → 40, 11, 22, 03, 34 A → 30, 41, 12, 23, 04 R → 55, 86, 67, 98, 79
First option: 13, 11, 12, 78
Question : Directions: In the following question, a sentence is given with a blank that is to be filled in with an appropriate word. Four alternatives are suggested; choose the correct alternative out of them as your answer. For ____ sake don't tell it to others.
Option 1: haven
Option 2: heaven
Option 3: heavens
Option 4: heaven's
Correct Answer: heaven's
Solution : The fourth option is the correct answer.
In this context, the sentence expresses a plea or a request not to tell something to others for the sake of something or someone. The idiom, "For heaven's sake" is used to show frustration, urgency, or emphasis on
Question : "India House", a revolutionary organisation, was established by Shyamji Krishna Varma in ______ for the spread of Indian Nationalism.
Option 1: Singapore
Option 2: London
Option 3: San Francisco
Option 4: Paris
Correct Answer: London
Solution : The correct option is London.
India House, a revolutionary organisation, was established by Shyamji Krishna Varma in London in 1905 for the spread of Indian Nationalism. This organisation played a significant role in the Indian independence movement and became a hub for Indian nationalists and
Question : If 80 litres of milk solution has 60% milk in it, then how much milk should be added to make milk 80% in the solution?
Option 1: 70 litres
Option 2: 50 litres
Option 3: 60 litres
Option 4: 80 litres
Correct Answer: 80 litres
Solution : Given: 80 litres of milk solution has 60% milk in it. Milk in the solution $=\frac{60}{100}×80=48$ Water in the solution $80-48=32$ Let the added milk be $x$ litres to make milk 80% in the solution. So, $\frac{48+x}{80+x}=\frac{80}{100}$ $⇒240+5x=320+4x$ $\therefore x =80$ Hence, the correct
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