All Questions

Staff Selection Commission Combined Graduate Level Exam

Follow
Showing 7671 - 7680 out of 16717 Questions
17 Views

Question : Part IV of the Constitution of India deals with which of the following?

Option 1: The Union

Option 2: The States

Option 3: Fundamental Rights

Option 4: Directive Principles of State Policy

Team Careers360 15th Jan, 2024

Correct Answer: Directive Principles of State Policy


Solution : The Correct Answer is Directive Principles of State Policy

The Directive Principles of State Policy (DPSP) are found in Part IV of the Indian Constitution, Articles 36–51. These tenets seek to create a welfare state in India and guarantee socioeconomic

19 Views

Question : The expression $\frac{\tan ^6 \theta-\sec ^6 \theta+3 \sec ^2 \theta \tan ^2 \theta}{\tan ^2 \theta+\cot ^2 \theta+2}, 0^{\circ}<\theta<90^{\circ}$, is equal to:

Option 1: $\sec ^2 \theta \operatorname{cosec}^2 \theta$

Option 2: $-\sec ^2 \theta \operatorname{cosec}^2 \theta$

Option 3: $\cos ^2 \theta \sin ^2 \theta$

Option 4: $-\cos ^2 \theta \sin ^2 \theta$

Team Careers360 21st Jan, 2024

Correct Answer: $-\cos ^2 \theta \sin ^2 \theta$


Solution : $\frac{\tan ^6 \theta-\sec ^6 \theta+3 \sec ^2 \theta \tan ^2 \theta}{\tan ^2 \theta+\cot ^2 \theta+2}$
Since $0^{\circ}<\theta<90^{\circ}$, putting $\theta=45^{\circ}$
$\frac{\tan ^6 45^{\circ}-\sec ^6 45^{\circ}+3 \sec ^2 45^{\circ} \tan ^2 45^{\circ}}{\tan ^2 45^{\circ}+\cot ^245^{\circ}+2}$
$=\frac{1-(\sqrt2)^6+ 3\times (\sqrt2)^2\times 1}{1+1+2}$
$=\frac{1-8+6}{1+1+2}=-\frac{1}{4}$
From option

12 Views

Question : Directions: How many triangles are there in the given figure?

Option 1: 14

Option 2: 15

Option 3: 16

Option 4: 19

Team Careers360 14th Jan, 2024

Correct Answer: 15


Solution : The figure can be labeled as shown below –

There are a total of 15 triangles in the figure. They are AHB, AHD, BHC, DHC, ABD, BCD, BAC, ADC, EHC, CHF, GHF, CHG, BHE, DHG, DHF.

Hence, the second option is correct.

23 Views

Question : Simplify the given expression.
$
\frac{432 \times 432+247 \times 247-432 \times 247}{432 \times 432 \times 432+247 \times 247 \times 247}
$

Option 1: $\frac{1}{259}$

Option 2: $\frac{1}{185}$

Option 3: $\frac{1}{679}$

Option 4: $\frac{1}{450}$

Team Careers360 15th Jan, 2024

Correct Answer: $\frac{1}{679}$


Solution : $\frac{432^2+247^2-432 \times 247}{432^3+247^3}$
Using identity $x^3+y^3 = (x+y)(x^2+y^2-x \times y)$, 
$\frac{432^2+247^2-432 \times 247}{(432+247)(432^2+247^2-432 \times 247)}$
$=\frac{1}{(432+247)}$
$= \frac{1}{679}$
Hence, the correct answer is $\frac{1}{679}$.

9 Views

Question : Directions: In the following question, some parts of the sentence have errors, and some are correct. Find out which part of the sentence has an error. The number of that part is the answer. If a sentence is error-free, your answer is "No Error".

Could she cite (1) / any precedent in support (2) / for her case? (3) / No Error (4)

Option 1: 1

Option 2: 2

Option 3: 3

Option 4: 4

Team Careers360 23rd Jan, 2024

Correct Answer: 3


Solution : The error lies in the third part of the sentence.

Explanation: The preposition "for" is incorrect in this context. When talking about supporting something, the correct preposition to use is "of". The term "in support of" means strengthening something.

Hence, the correct sentence should be:

12 Views

Question : Direction: In each of the following question, which one set of letters when sequentially placed at the gaps in the given letter series shall complete it?

SH _ ELAS _ EELA _ HEELASHEE _ A

Option 1: HHSS

Option 2: EEHS

Option 3: EHSL

Option 4: ELHA

Team Careers360 25th Jan, 2024

Correct Answer: EHSL


Solution : Given:

SH _ ELAS _ EELA _ HEELASHEE _ A

We have to check the order of the letters in the given series.

To fill the series we have to divide the series, SH _ / ELA / S _ E/ ELA / _  HE

19 Views

Question : If $y+\frac{1}{y}=11$, then the value of $y^3-\frac{1}{y^3}$ is:

Option 1: $345 \sqrt{13}$

Option 2: $360 \sqrt{13}$

Option 3: $352 \sqrt{13}$

Option 4: $368 \sqrt{13}$

Team Careers360 15th Jan, 2024

Correct Answer: $360 \sqrt{13}$


Solution : Given, $y+\frac{1}{y}=11$
Squaring both sides, we get:
$⇒(y+\frac{1}{y})^2=11^2$
$⇒(y-\frac{1}{y})^2+4(y)(\frac{1}y)=121$
$⇒(y-\frac{1}{y})^2+4=121$
$⇒(y-\frac{1}{y})^2=121-4$
$⇒(y-\frac{1}{y})=3\sqrt{17}$
Cubing both sides, we get:
$⇒(y-\frac{1}{y})^3=(3\sqrt{17})^3$
$⇒y^3-\frac{1}{y^3}-3(y)(\frac{1}{y})(y-\frac{1}{y})=351\sqrt{13}$
$⇒y^3-\frac{1}{y^3}-3(3\sqrt{17})=351\sqrt{13}$
​​​​​​$⇒y^3-\frac{1}{y^3}=351\sqrt{13}+9\sqrt{13}$
$\therefore y^3-\frac{1}{y^3}=360\sqrt{13}$
Hence, the correct answer is $360\sqrt{13}$.

18 Views

Question : Directions: In a certain code language, if PDFJARS is written as OCELZQR and MHCXBTU is written as LGBZAST, how will ZVDGENQ be written in the same code language?

Option 1: XUYCIMP

Option 2: YUCIDMP

Option 3: XUCDEMQ

Option 4: XVDEDNO

Team Careers360 25th Jan, 2024

Correct Answer: YUCIDMP


Solution : Given:
PDFJARS is written as OCELZQR.
MHCXBTU is written as LGBZAST.

Subtract 1 from the place values of the letters except the middle one; add 2 to the place value of the letter in the middle of the given word.
Like, PDFJARS→P – 1 =

The question have been saved in answer later, you can access it from your profile anytime. Access now