Staff Selection Commission Combined Graduate Level Exam
Question : A man can row 10 km/hr in still water. When the river is running at a speed of 4.5 km/hr, then it takes him 2 hours to row to a place and comes back to the initial point. How far is the place (in km) (rounded off to two decimal places)?
Option 1: 5.50
Option 2: 8.98
Option 3: 7.98
Option 4: 6.25
Correct Answer: 7.98
Solution : Downstream speed = (10 + 4.5) = 14.5 km/hr Upstream speed = (10 – 4.5) = 5.5 km/hr Let the distance be $x$ km. According to the question, $\frac{x}{14.5}+\frac{x}{5.5}=2$ ⇒ $\frac{10x}{145}+\frac{10x}{55}=2$ ⇒ $550x+1450x=2×145×55$ ⇒ $2000x=2×145×55$ ⇒ $x=\frac{2×145×55}{2000}$ ⇒ $x= 7.975 \approx 7.98$ km Hence, the
Question : Direction: In the following question, select the one which is different from the other three alternatives.
Option 1: 36
Option 2: 96
Option 3: 16
Option 4: 80
Correct Answer: 36
Solution : Let's check the options —
First option: 36; 36 is not divisible by 16. This option is different from the other options.
Second option: 96; 96 ÷ 16 = 6. 96 is divisible by 16.
Third option: 16; 16 ÷ 16 = 1. 16 is
Option 1: 42 : 4
Option 2: 48 : 6
Option 3: 32 : 2
Option 4: 15 : 5
Correct Answer: 42 : 4
First option: 42 : 4; 42 is not divisible by 4. This option is different from the other options.
Second option: 48 : 6; 48 ÷ 6 = 8. 48 is divisible by 6.
Third option: 32 :
Question : Who has instituted the "Moortidevi Sahitya Puraskar"?
Option 1: Ministry of HRD, Central Government
Option 2: Sahitya Academy
Option 3: Bharatiya Jnanapeeth Trust
Option 4: Bharatiya Vidya Bhavan
Correct Answer: Bharatiya Jnanapeeth Trust
Solution : The correct answer is Bharatiya Jnanapeeth Trust. mo
The Bharatiya Jnanpeeth Trust, bestows the Moortidevi Award to an Indian writer each year. It was instituted in the year 1961 but was first awarded in 1983. It has a cash reward of 4 lakh
Question : Find the smallest number that can be subtracted from 148109326 so that it becomes divisible by 8.
Option 1: 4
Option 2: 8
Option 3: 6
Option 4: 10
Correct Answer: 6
Solution : Given: Number = 148109326 The last three digits of the given number are 326. When 326 is divided by 8 gave a remainder of 6. So, 148109326 – 6 = 148109320 is completely divisible by 8. So, the smallest required number is 6. Hence, the
Question : Part IV of the Constitution of India deals with which of the following?
Option 1: The Union
Option 2: The States
Option 3: Fundamental Rights
Option 4: Directive Principles of State Policy
Correct Answer: Directive Principles of State Policy
Solution : The Correct Answer is Directive Principles of State Policy
The Directive Principles of State Policy (DPSP) are found in Part IV of the Indian Constitution, Articles 36–51. These tenets seek to create a welfare state in India and guarantee socioeconomic
Question : The expression $\frac{\tan ^6 \theta-\sec ^6 \theta+3 \sec ^2 \theta \tan ^2 \theta}{\tan ^2 \theta+\cot ^2 \theta+2}, 0^{\circ}<\theta<90^{\circ}$, is equal to:
Option 1: $\sec ^2 \theta \operatorname{cosec}^2 \theta$
Option 2: $-\sec ^2 \theta \operatorname{cosec}^2 \theta$
Option 3: $\cos ^2 \theta \sin ^2 \theta$
Option 4: $-\cos ^2 \theta \sin ^2 \theta$
Correct Answer: $-\cos ^2 \theta \sin ^2 \theta$
Solution : $\frac{\tan ^6 \theta-\sec ^6 \theta+3 \sec ^2 \theta \tan ^2 \theta}{\tan ^2 \theta+\cot ^2 \theta+2}$ Since $0^{\circ}<\theta<90^{\circ}$, putting $\theta=45^{\circ}$ $\frac{\tan ^6 45^{\circ}-\sec ^6 45^{\circ}+3 \sec ^2 45^{\circ} \tan ^2 45^{\circ}}{\tan ^2 45^{\circ}+\cot ^245^{\circ}+2}$ $=\frac{1-(\sqrt2)^6+ 3\times (\sqrt2)^2\times 1}{1+1+2}$ $=\frac{1-8+6}{1+1+2}=-\frac{1}{4}$ From option
Question : Directions: How many triangles are there in the given figure?
Option 1: 14
Option 2: 15
Option 4: 19
Correct Answer: 15
Solution : The figure can be labeled as shown below –
There are a total of 15 triangles in the figure. They are AHB, AHD, BHC, DHC, ABD, BCD, BAC, ADC, EHC, CHF, GHF, CHG, BHE, DHG, DHF.
Hence, the second option is correct.
Question : Simplify the given expression. $ \frac{432 \times 432+247 \times 247-432 \times 247}{432 \times 432 \times 432+247 \times 247 \times 247} $
Option 1: $\frac{1}{259}$
Option 2: $\frac{1}{185}$
Option 3: $\frac{1}{679}$
Option 4: $\frac{1}{450}$
Correct Answer: $\frac{1}{679}$
Solution : $\frac{432^2+247^2-432 \times 247}{432^3+247^3}$ Using identity $x^3+y^3 = (x+y)(x^2+y^2-x \times y)$, $\frac{432^2+247^2-432 \times 247}{(432+247)(432^2+247^2-432 \times 247)}$ $=\frac{1}{(432+247)}$ $= \frac{1}{679}$ Hence, the correct answer is $\frac{1}{679}$.
Question : Comprehension: In the following passage, some words have been deleted. Read the passage carefully and select the most appropriate option to fill in each blank. India is one of the largest producers of tea in the world. The industry is (1)________ recognised as technically very well (2) ________. The Indian tea industry is a (3) ________one traditionally. Tea has been used in India for (4) ________ purposes as well as for (5) ________. Question Select the most appropriate option to fill in the blank number 2.
Option 1: complex
Option 2: establish
Option 3: pampered
Option 4: equipped
Correct Answer: equipped
Solution : The most appropriate option to fill in the blank is the fourth option.
Explanation: The word technically in the sentence indicates that the industry is being described in terms of technical aspects. The adjective equipped fits well in this context, suggesting that the Indian tea
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