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Hello Student,
I totally understand how frustrating it can be to lose important documents. Yes, you can usually get a duplicate Long Mark Memo for 2026 if the original is lost. The process can vary depending on your examining board, though.
Typically, you'll need to reach out to them directly,
Hello Student, your chances for BPT at Banarsidas Chandiwala Institute of Physiotherapy or ISIC depend on the category, counselling round, seat availability and previous closing ranks. I would not want to guarantee a seat based only on rank.
Hi Romio Marak
Yes. Since Class 9 final exam papers depend on the board/state and subject, please specify the board/state, class, and subject so I can provide the correct 2026 final exam question paper.
You can also check
https://school.careers360.com/download/ebooks-and-sample-papers
Hey there,
If you mean the Kerala e-Grantz Post-Matric Scholarship, it is an online scholarship system for eligible SC, ST and OBC students studying after Class 10. Applications and scholarship assistance are processed through the official e-Grantz 3.0 portal.
Thanks
Nischal
Hi!
Please specify your state/board, this will help us answer you with the best resources.
Meanwhile, check the link below, apply relevant filters, find suitable resources:
Hope it helps!
The link to download the Karnataka school exam model paper is given here:
https://school.careers360.com/boards/kseeb/karnataka-sslc-10th-model-papers-2026-27
Given: Density of sphere, $\rho_s=8 \mathrm{~g} / \mathrm{cm}^3$ First medium: specific gravity $=2$, so $\rho_1=2 \mathrm{~g} / \mathrm{cm}^3$ Second medium: specific gravity $=4$, so $\rho_2=4 \mathrm{~g} / \mathrm{cm}^3$ First angle: $90^{\circ}$ Second angle: $120{ }^{\circ}$ Dielectric constants: $k$ and $k^{\prime}$
For two identical charged spheres,
$ \tan \frac{\theta}{2}=\frac{F_e}{W_{\text {effective }}}
To find the X-component of the force on -q1, we need to know the positions of -q1, q2 and -q3, along with the distances/angles shown in the figure. The X-component is obtained by calculating the Coulomb force due to each charge and then resolving the forces along the
$ \begin{aligned} &\text { After an elongation of r, the separation between the charges will be ' } 2 r^{\prime}\\ &\begin{gathered} \frac{1}{4 \pi \epsilon_0} \times \frac{q^2}{2 r}=\frac{1}{2} k r^2 \\ k=\sqrt{\frac{q^2}{4 \pi \epsilon_0 r^3}}=\frac{q}{2 r} \sqrt{\frac{1}{\pi \epsilon_0 r}} \end{gathered} \end{aligned} $
If you mean how to get/download the e-books for Class 9 from CM SHRI Schools, the exact portal depends on the state because “CM SHRI School” is used for different state programmes.
If you mean Delhi CM SHRI Schools, tell me that and I can give you the
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