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Hey! Based on your details (Rank 62460, ST – Lambada, 722 marks in IPE), getting a free seat worth 7,50,000 will depend on the cutoff for your category in the current year. Usually, for reserved categories like ST, the cutoff is lower compared to General, so you do have some chances.

However, admission is not guaranteed because it also depends on:

Number of seats available in your course.

The demand for that branch.

Counselling rounds and how many students ahead of you choose.

Hello candidate,

Career360 provides mock tests , modal papers , practice questions , and previous year question papers. To help students to prepare for exams .

Here is a link attached, for CUET MCQ question with answer(All subject )

https://university.careers360.com/articles/cuet-mcqs

Hope this information is useful to you.

Hey! To get an M.Sc. Nursing Eligibility Certificate in Maharashtra, first make sure you have a B.Sc. Nursing or Post Basic B.Sc. Nursing degree and are registered with the Maharashtra Nursing Council (MNC) or any State Nursing Council. You should also have at least one year of work experience after your B.Sc. degree.

Then, collect all necessary documents like your degree certificate, mark sheets, MNC/INC registration, experience certificate, medical fitness certificate, and passport-size photos. Submit these along with the application form at the Maharashtra Nursing Council office in Mumbai and pay the required fee. After verification, they will issue your eligibility certificate, which you can use to apply for M.Sc. Nursing admissions.

Hey! If your EWS admission in Maharashtra got rejected because you belong to the Maratha caste, it can feel unfair. Since the CET Cell is not converting your seat to open category or allowing cancellation, the best way is to check all your documents carefully, contact the CET Cell directly to explain your situation, and use the grievance redressal system. Also, keep your institute informed so you don’t miss any opportunity in the next round.

Hello,

To find pseb class 12 chemistry sample papers for the 2025 exam here is a link attached

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If you have one subject pending in 12th, you cannot take admission immediately. Most colleges and entrance exams, including MHT CET in Maharashtra, require you to have passed all 12th subjects. You should wait for your result of the pending subject. Once you pass, you can apply for admission. Meanwhile, you can plan your preparation for next year or keep an eye on any special rounds if allowed.

Hello dear candidate,

last year CUET ICAR UG rank for OBC category for B.Sc. agriculture is around 340+ marks for round 1 cutoffs.

We could give you a more precise if you specify which university or state.

Hey! With your AP LAWCET rank of 3992 in the SC category, here’s an idea of your chances for the colleges you chose:

DNR College, Bhimavaram – This one might be tough as SC closing ranks are usually lower than your rank.

JC College, Guntur – Your rank is within a reasonable range, so chances are good.

GSK College, Rajahmundry – You have a fair chance here too.

Siddhartha College, Vijayawada – Your rank is competitive for this college.

It’s a good idea to add a few more colleges in your web options to improve your chances. Also, keep checking the seat allotment updates and be ready to confirm any seat that comes up.

Hey! If you want to make changes in your GATE application after submission, you can do it through the correction window on the official GOAPS website. Log in with your enrollment ID or email and password, click on Application Form Correction, and make the necessary edits like personal details, academic info, exam paper, category, or exam centre. Some changes may require a small fee. After editing, submit the form and download the updated copy for your records.

Remember, the correction window is open for a limited time, so make the changes before the deadline.

Hello,

The value of k is 6.

Explanation

1. Understand the Formula

For any quadratic polynomial in the standard form ax² + bx + c, the product of its zeroes (roots) is given by the formula:

Product of the zeroes = c/a

2. Identify the Coefficients

First, let's identify the values of a, b, and c from your given polynomial:

p(x) = 2x² - 3x + k

Comparing this to the standard form, we have:

• a = 2

• b = -3

• c = k

3. Set Up the Equation

The problem states that the product of the zeroes is 3.

Using the formula, we know the product of the zeroes is also c/a. So, we can set up the following equation:

c/a = 3

4. Solve for k

Now, substitute the values of 'a' and 'c' from the polynomial into the equation:

k/2 = 3

To find k, multiply both sides of the equation by 2:

k = 3 * 2

k = 6

Therefore, the value of k is 6.