It's a Question of your Career!

Correct Answer: (99, 82, 71)

Solution : Given:
(53, 36, 25); (71, 54, 43)

In the above-given set of numbers, divide the sum of the first and third numbers by 2 and subtract 3 from the resultant to get the second number –
⇒(53, 36, 25)→{(53 + 25) ÷ 2}

Correct Answer: Brahmo Samaj

Solution : The correct option is Brahmo Samaj.

Raja Ram Mohan Roy founded the Brahmo Sabha, which was later known as the Brahmo Samaj. Raja Ram Mohan Roy established the Brahmo Samaj to promote monotheism, the worship of the formless divine, and opposing idol worship.

Correct Answer: Kosi

Solution : The correct option is Kosi.

Kosi is not a tributary of the Indus River system. It flows through the Indian states of Bihar and Nepal, ultimately joining the Ganges. In contrast, the Indus River system comprises tributaries such as the Jhelum, Chenab, Ravi, Beas and

Correct Answer: $96 \pi$

Solution : The radius of the base of a cylindrical tank, $r$ = 4 m
Let the height of the cylinder be $h$.
According to the question,
Three times the sum of the areas of its two circular faces is twice the area of its curved

Correct Answer: Carnatic Music

Solution : The correct option is Carnatic Music

Kuchipudi, a classical dance form that originated in the state of Andhra Pradesh in India, is traditionally accompanied by Carnatic music. Carnatic music is a form of classical music that has its roots in South India. In this

Correct Answer: $\frac{\mathrm{k}^{64}-\frac{1}{\mathrm{k}^{64}}}{\mathrm{k}+\frac{1}{\mathrm{k}}}$

Solution : $
\left(\mathrm{k}-\frac{1}{\mathrm{k}}\right)\left(\mathrm{k}^2+\frac{1}{\mathrm{k}^2}\right)\left(\mathrm{k}^4+\frac{1}{\mathrm{k}^4}\right)\left(\mathrm{k}^8+\frac{1}{\mathrm{k}^8}\right)\left(\mathrm{k}^{16}+\frac{1}{\mathrm{k}^{16}}\right)\left(\mathrm{k}^{32}+\frac{1}{\mathrm{k}^{32}}\right)
$
Multiplying and dividing by $(\mathrm{k}+\frac{1}{\mathrm{k}})$
= $
\frac{(\mathrm{k}+\frac{1}{\mathrm{k}})\left(\mathrm{k}-\frac{1}{\mathrm{k}}\right)\left(\mathrm{k}^2+\frac{1}{\mathrm{k}^2}\right)\left(\mathrm{k}^4+\frac{1}{\mathrm{k}^4}\right)\left(\mathrm{k}^8+\frac{1}{\mathrm{k}^8}\right)\left(\mathrm{k}^{16}+\frac{1}{\mathrm{k}^{16}}\right)\left(\mathrm{k}^{32}+\frac{1}{\mathrm{k}^{32}}\right)}{(\mathrm{k}+\frac{1}{\mathrm{k}})}
$
= $
\frac{(\mathrm{k}^2-\frac{1}{\mathrm{k}^2})\left(\mathrm{k}^2+\frac{1}{\mathrm{k}^2}\right)\left(\mathrm{k}^4+\frac{1}{\mathrm{k}^4}\right)\left(\mathrm{k}^8+\frac{1}{\mathrm{k}^8}\right)\left(\mathrm{k}^{16}+\frac{1}{\mathrm{k}^{16}}\right)\left(\mathrm{k}^{32}+\frac{1}{\mathrm{k}^{32}}\right)}{(\mathrm{k}+\frac{1}{\mathrm{k}})}
$
= $
\frac{(\mathrm{k}^4-\frac{1}{\mathrm{k}^4})\left(\mathrm{k}^4+\frac{1}{\mathrm{k}^4}\right)\left(\mathrm{k}^8+\frac{1}{\mathrm{k}^8}\right)\left(\mathrm{k}^{16}+\frac{1}{\mathrm{k}^{16}}\right)\left(\mathrm{k}^{32}+\frac{1}{\mathrm{k}^{32}}\right)}{(\mathrm{k}+\frac{1}{\mathrm{k}})} 
$
= $
\frac{(\mathrm{k}^8-\frac{1}{\mathrm{k}^8})\left(\mathrm{k}^8+\frac{1}{\mathrm{k}^8}\right)\left(\mathrm{k}^{16}+\frac{1}{\mathrm{k}^{16}}\right)\left(\mathrm{k}^{32}+\frac{1}{\mathrm{k}^{32}}\right)}{(\mathrm{k}+\frac{1}{\mathrm{k}})}
$
= $
\frac{(\mathrm{k}^{16}-\frac{1}{\mathrm{k}^{16}})\left(\mathrm{k}^{16}+\frac{1}{\mathrm{k}^{16}}\right)\left(\mathrm{k}^{32}+\frac{1}{\mathrm{k}^{32}}\right)}{(\mathrm{k}+\frac{1}{\mathrm{k}})}
$
= $\frac{(\mathrm{k}^{32}-\frac{1}{\mathrm{k}^{32}})\left(\mathrm{k}^{32}+\frac{1}{\mathrm{k}^{32}}\right)}{(\mathrm{k}+\frac{1}{\mathrm{k}})}
$
= $\frac{(\mathrm{k}^{64}-\frac{1}{\mathrm{k}^{64}})}{(\mathrm{k}+\frac{1}{\mathrm{k}})} $
Hence, the correct answer is $\frac{(\mathrm{k}^{64}-\frac{1}{\mathrm{k}^{64}})}{(\mathrm{k}+\frac{1}{\mathrm{k}})}$.

Correct Answer: Vasco da Gama

Solution : The correct answer is Vasco da Gama

Vasco da Gama discovered a sea route to India in 1498. He was a Portuguese navigator. He was the first European to reach India by sailing through Africa. He reached Calicut during the reign of the

Correct Answer: –1

Solution : Given:
$x^{2}+y^{2}+2x+1=0$
⇒ $x^{2}+2x+1+y^{2}=0$
⇒ $(x+1)^2+y^2=0$
Since the addition of the squares of the two terms is zero,
So, both the terms are individually zero.
Therefore, $(x+1)^2=0$ and $y^2=0$.
⇒ $x=-1$ and $y=0$
Now, $x^{31}+y^{35}$
= $(-1)^{31}+(0)^{35}$
= –1
Hence, the correct answer is –1.

Correct Answer: (3)

Solution : The error lies in the third part of the sentence.

The preposition that should follow "senior" is to as adjectives ending in "-ior", such as junior, senior, inferior, and superior, are followed by to and not than.

Therefore, the correct sentence is: "She does

Correct Answer:

Solution : According to the given figures –
1. The circle in the box is moving in a clockwise direction from one corner to another.
2. The arrow inside the box is rotating by 90° in the anticlockwise direction.
3. The letters that are present in the box