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Question : Comprehension: In the following passage, some words have been deleted. Fill in the blanks with the help of the alternatives given. Select the most appropriate option for each number. In winter, when the snow (1)______ the higher ranges, the Himalayan bears come to (2)______ altitudes in search of food. Sometimes they forage (3)_______ the fields and because they are short-sighted and (4)______ of anything that moves, they can be (5)______. But, like most wild animals, they (6)_______ humans as much as possible. Village folk (7)______ advise me to run downhill if (8)______ by a bear. They say bears find it easier to run uphill (9)______ down. I am glad that I am (10)______ to be chased by a bear and will happily skip the experience. Question: Select the most appropriate option to fill in the blank No. 8.
Option 1: pushed
Option 2: hunted
Option 3: chased
Option 4: rushed
Correct Answer: chased
Solution : The third option is the correct answer.
The context suggests that village folk advise the speaker to run downhill if chased by a bear. The word, chased fits well in this context, indicating that the advice is specific to a situation where a person is
Question : Which of the following writers had called Akbar's Din-i Ilahi, a monument of his folly, not of wisdom?
Option 1: Badayuni
Option 2: Vincent Smith
Option 3: Barni
Option 4: W. Haig
Correct Answer: Vincent Smith
Solution : The correct answer is Vincent Smith.
Akbar founded the Din-i Ilahi religion in 1582. Birbal was reportedly the only Hindu supporter of that initiative, but it failed because the people were not interested in this. Author Vincent Smith referred to the Din-i Ilahi
Question : Directions: In the following question, select the missing number from the given series. 81, 94, 120, 159, 211, ?
Option 1: 266
Option 2: 278
Option 3: 276
Option 4: 264
Correct Answer: 276
Solution : Given: 81, 94, 120, 159, 211, ?
Add the consecutive multiples of 13 to each term to get the next term in the series. 81 + 13 = 94; 94 + 26 = 120; 120 + 39 = 159; 159 + 52 = 211; 211
Question : A man bought a watch at a 10% discount. If he had bought it at a 20% discount, he would have gotten the watch for Rs. 125 less. The marked price of the watch is:
Option 1: Rs. 2,500
Option 2: Rs. 1,250
Option 3: Rs. 3,750
Option 4: Rs. 1,000
Correct Answer: Rs. 1,250
Solution : Given: A man bought a watch at a 10% discount. If he had bought it at a 20% discount, he would have gotten the watch for Rs. 125 less. Here (20 – 10) = 10% is equivalent to Rs. 125 So 100% is equivalent
Question : If $\left (x+\frac{1}{x} \right)=5$, what is the value of $\left (x^{5}+\frac{1}{x^{5}} \right)$?
Option 1: 1875
Option 2: 2525
Option 3: 2530
Option 4: 3120
Correct Answer: 2525
Solution : Given: $\left (x+\frac{1}{x} \right)=5$ Squaring both sides, we get, $⇒\left (x+\frac{1}{x} \right )^{2}=5^{2}$ $⇒x^{2}+\frac{1}{x^{2}}+2=25$ $⇒x^{2}+\frac{1}{x^{2}}=23$ Also, $\left ( x+\frac{1}{x} \right )^{3}=5^{3}$ $⇒x^{3}+\frac{1}{x^{3}}+3(x)(\frac{1}{x})(x+\frac{1}{x})=125$ $⇒x^{3}+\frac{1}{x^{3}}+3(1)(5)=125$ $⇒x^{3}+\frac{1}{x^{3}}=110$ Now, $(x^{3}+\frac{1}{x^{3}})( x^2+\frac{1}{x^2})=x^{5}+\frac{1}{x^{5}}+x+\frac{1}{x}$ $⇒110\times 23=x^{5}+\frac{1}{x^{5}}+5$ $\therefore x^{5}+\frac{1}{x^{5}} = 2525$ Hence, the correct answer is 2525.
Question : Directions: Four pairs of letter clusters have been given out of which three are alike in some manner, while one is different. Choose the odd one.
Option 1: GJB – ROW
Option 2: EFR – VUI
Option 3: DFL – USM
Option 4: IKN – PNK
Correct Answer: EFR – VUI
Solution : Let's check each option: First Option: GJB – ROW; In the second letter cluster opposite alphabet are written of the first letter cluster; G→R; J→O; B→W Second Option: EFR – VUI→This doesn't follow the rule as R is not opposite to I. Third
Question : Directions: In the following question a series is given, with one term missing. Choose the correct alternative from the given ones that will complete the series. 7, 16, 27, 40, 55, ?
Option 1: 70
Option 2: 72
Option 3: 81
Option 4: 66
Correct Answer: 72
Solution : Given: 7, 16, 27, 40, 55, ?
Add consecutive odd numbers starting from 9 in each number, to get the next number in the series – 7 + 9 = 16; 16 + 11 = 27; 27 + 13 = 40; 40 + 15 =
Question : In how much time will a sum of Rs. 10200 amount to Rs. 19125 at the rate of 12.5% per annum at simple interest?
Option 1: 6 years
Option 2: 5 years
Option 3: 8 years
Option 4: 7 years
Correct Answer: 7 years
Solution : Given, Principal Amount, $P$ = Rs. 10200 The amount received after interest = Rs. 19125 Rate of interest, $R$ = 12.5% Let the time taken for the amount to become Rs. 19125 be $T$ years Simple interest here = Rs. (19125 – 10200) =
Question : Having started from the same point simultaneously, two runners P and Q are running around a circular track of length 500 m in opposite directions with speeds of 6 m/s and 10 m/s, respectively. If they exchange their speeds after meeting for the first time, who will reach the starting point first?
Option 1: Q
Option 2: P
Option 3: Both P and Q will reach at the same time
Option 4: No one of the P and Q
Correct Answer: Both P and Q will reach at the same time
Solution : Two runners P and Q run in a circular track of length with speeds 6 m/s and 10 m/s. The time they meet for the first time $=\frac{\text{Length of Circular Track}}{\text{Relative Speed}}$ $= \frac{500}{10 + 6}
Question : If $x:y=3:4$, then $4x+5y:5x–2y=?$
Option 1: $7:32$
Option 2: $32:7$
Option 3: $4:3$
Option 4: $5:2$
Correct Answer: $32:7$
Solution : Given: $x:y=3:4$ --------------------------------(1) Or, $\frac{x}{y}=\frac{3}{4}$ Now, $(4x+5y):(5x–2y)$ Dividing by $y$ in the numerator and the denominator, we get, $[4(\frac{x}{y})+5]:[5(\frac{x}{y})–2]$ = $[4(\frac{3}{4})+5:5(\frac{3}{4})–2]$ (Putting the value of $\frac{x}{y}$ from equation 1) = $(3+5):(\frac{15}{4}–2)$ = $8:(\frac{15–8}{4})$ = $8:\frac{7}{4}$ = $32:7$ Hence, the correct answer is $32:7$.
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