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Question : Select the most appropriate option that can substitute the underlined segment in the given sentence. I like all games instead of cricket.
Option 1: rather
Option 2: exclude
Option 3: object
Option 4: except
Correct Answer: except
Solution : The correct choice is the fourth option.
Explanation: The most suitable option to replace the underlined segment in the sentence is "except". This is because "except" conveys the idea of excluding or not including cricket in the list of favourite games.
Therefore, the correct sentence
Question : Directions: In the following question, select the odd letter/letters from the given alternatives.
Option 1: ONKP
Option 2: EDAZ
Option 3: YXUF
Option 4: IHEW
Correct Answer: IHEW
Solution : Let's check the options – First option: ONKP→O – 1 = N; N – 3 = K; K and P are opposite pairs. Second option: EDAZ→E – 1 = D; D – 3 = A; A and Z are opposite pairs. Third option: YXUF→Y –
Question : Directions: Select the option figure that is embedded in the given figure (rotation is not allowed).
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : Since there is a restriction on the rotation of the figure, we will check which of the option figures can exactly fit in the given question figure. By comparison of all the option figures, only the second option figure is embedded in the given question figure.
Question : If $\cos \theta=\frac{12}{13}$, then the value of $\frac{\sin \theta(1-\tan \theta)}{\tan \theta(1+\operatorname{cosec} \theta)}$ is:
Option 1: $\frac{25}{78}$
Option 2: $\frac{35}{234}$
Option 3: $\frac{35}{108}$
Option 4: $\frac{25}{156}$
Correct Answer: $\frac{35}{234}$
Solution : Given: $\cos \theta=\frac{12}{13}$ We know that, $\cos \theta=\frac{\text{Base}}{\text{Hypotenuse}}=\frac{12}{13}$ Using Pythagoras theorem, we get, Perpendicular = $\sqrt{13^2-12^2}=5$ $\sin \theta=\frac{\text{Perpendicular}}{\text{Hypotenuse}}=\frac{5}{13}$ $\tan \theta=\frac{\text{Perpendicular}}{\text{Base}}=\frac{5}{12}$ $\operatorname{cosec} \theta=\frac{1}{\sin \theta}=\frac{13}{5}$ Now, $\frac{\sin \theta(1-\tan \theta)}{\tan \theta(1+\operatorname{cosec} \theta)}$ $= \frac{\frac{5}{13}(1-\frac{5}{12})}{\frac{5}{12}(1+\frac{13}{5})}$ $= \frac{\frac{5}{13}\times \frac{7}{12}}{\frac{5}{12}\times \frac{18}{5}}$ $=\frac{35}{234}$ Hence, the correct answer is $\frac{35}{234}$.
Question : Directions: Study the given pattern carefully and select the number that can replace the question mark (?) in it. First row – 15, 11, 43 Second row – 13, 8, 48 Third row – 9, 7, ? (NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into their constituent digits. E.g. 13 – Operations on 13 such as adding/subtracting/multiplying, etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is NOT allowed.)
Option 1: 23
Option 2: 30
Option 3: 27
Option 4: 26
Correct Answer: 23
Solution : Given: First row – 15, 11, 43 Second row – 13, 8, 48 Third row – 9, 7, ?
Like, (15 – 11) × 8 = 4 × 8 = 32; 32 + 11 = 43 (13 – 8) × 8 = 5 × 8
Question : The rate at which the Reserve Bank of India lends to other commercial banks for the short term has been reduced. What is this rate called?
Option 1: Cash Reserve Rate
Option 2: Reverse Repo Rate
Option 3: Bank Rate
Option 4: Repo Rate
Correct Answer: Repo Rate
Solution : The correct option is the Repo Rate.
The rate at which the Reserve Bank of India (RBI) lends to other commercial banks for the short term is called the repo rate. When the RBI reduces the repo rate, it is typically done to
Question : Which of the following universities secured the top place in the medal tally of the "Khelo India University Games 2020"?
Option 1: Delhi University
Option 2: Punjab University
Option 3: Savitribai Phule University
Option 4: Jawaharlal Nehru University
Correct Answer: Punjab University
Solution : The correct answer is Punjab University.
In the 2020 edition of the Khelo India competition, a total of 206 gold, 206 silver and 286 bronze medals were conferred. Fencing and Rugby made their debut in this edition. Punjab University stood out as the
Question : Directions: Select the figure from among the given options that can replace the question mark (?) in the following series.
Solution : Here the pattern is as follows — 1. From box 1 to box 2 – The first arrow interchanges its position with the second arrow, the third arrow interchanges position with the fourth arrow, and all the arrows flip vertically. 2. From box 2 to box
Question : A merchant marks an article 20% above the cost price. He then sells it at a discount of 20%. The sale gives him:
Option 1: No loss no gain
Option 2: 4% loss
Option 3: 2% gain
Option 4: 4% gain
Correct Answer: 4% loss
Solution : Given: A merchant marks an article 20% above the cost price. He then sells it at a discount of 20%. Let the cost price be 100 units. Now marked price = 120 units So, Selling price = $\frac{120}{100}×80=96$ Loss = 100 – 96 =
Question : Directions: In this question, a word is represented by only one set of numbers as given in any one of the alternatives. The sets of numbers given in the alternatives are represented by two classes of alphabets as in the two matrices, given below. The columns and rows of Matrix (I) are numbered from 0 to 4 and that of Matrix (II) are numbered from 5 to 9. A letter from these matrices can be represented first by its row and next by its column, e.g. D can be represented by 68, 10, etc, and R can be represented by 34, 22, etc. Similarly, you have to identify the set for the word PRIME.
Option 1: 42, 31, 20, 79, 57
Option 2: 33, 34, 11, 97, 56
Option 3: 95, 13, 02, 14, 23
Option 4: 30, 22, 00, 65, 99
Correct Answer: 33, 34, 11, 97, 56
Solution : Given: PRIME
Number representations of each letter – P→01, 30, 33, 42, 95 R→04, 13, 22, 31, 34, 40 I→00, 02, 11 M→03, 65, 79, 97 E→24, 32, 41, 56
First option: 42, 31, 20, 79, 57; I and E cannot
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