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15 Views

Question : Find the area of the rhombus whose diagonals are 16 cm and 20 cm.

Option 1: 110 cm2

Option 2: 150 cm2

Option 3: 160 cm2

Option 4: 120 cm2

Team Careers360 24th Jan, 2024

Correct Answer: 160 cm2


Solution : $D_1$ = 16 cm
$D_1$ = 20 cm
Area of rhombus = $\frac{1}{2}D_1D_2=\frac{1}{2}×16×20=160\;cm^2$
Hence, the correct answer is 160 cm2.

15 Views

Question : An article was sold for INR 98,496 after providing three successive discounts of 10%, 5%, and 4% respectively on the marked price. What was the marked price?

Option 1: INR 1,20,000

Option 2: INR 1,10,700

Option 3: INR 1,20,200

Option 4: INR 1,20,500

Team Careers360 23rd Jan, 2024

Correct Answer: INR 1,20,000


Solution : For three successive discounts of 10%, 5%, and 4%, Selling price = $\frac{100-\text{Discount}_1\%}{100}× \frac{100-\text{Discount}_2\%}{100}×\frac{100-\text{Discount}_3\%}{100}×$ marked price
$⇒ 98496=\frac{100-10}{100}×\frac{100-5}{100}×\frac{100-4}{100}×$ marked price
$⇒ 98496=\frac{90}{100}×\frac{95}{100}×\frac{96}{100}×$ marked price
$\therefore$ Mrked price $= 120000$
Hence, the correct answer is INR 1,20,000.

22 Views

Question : A boy increases his speed to $\frac{9}{5}$th times of his original speed. By doing this, he reaches his school 40 minutes before the usual time. How much time (in minutes) does he usually take?

Option 1: 120

Option 2: 30

Option 3: 90

Option 4: 45

Team Careers360 22nd Jan, 2024

Correct Answer: 90


Solution : Let the speed of the boy be $x$ km/hr.
Initial time = $t$
So, distance = $tx$
New time = $t-40$
New speed = $x × (\frac{9}{5})=\frac{9x}{5}$
According to the question,
$tx=(t-40)\frac{9x}{5}$
$⇒5t=9t-360$
$⇒ 4t=360$
$\therefore t =90$ minutes
Hence, the correct answer is 90.

16 Views

Question : A class has five sections that have 25, 30, 40, 45, and 60 students, respectively. The pass percentages of these sections are 20%, 30%, 35%, 40%, and 100% respectively. The pass percentage of the entire class is:

Option 1: 87%

Option 2: 63%

Option 3: 53%

Option 4: 79%

Team Careers360 24th Jan, 2024

Correct Answer: 53%


Solution : Total number of students = 25 + 30 + 40 + 45 + 60 = 200
Number of students pass in Section A  = 25 × $\frac{20}{100}$ = 5
The number of students passed in Section B = 30 × $\frac{30}{100}$ = 9
The number

80 Views

Question : Directions: When a number X is added to the double of its cube, the number 1467 is obtained. Find the value of X.

Option 1: 6

Option 2: 9

Option 3: 7

Option 4: 8

Team Careers360 24th Jan, 2024

Correct Answer: 9


Solution : Let the number be X
X + 2(X)3 = 1467

Let's check each option –
First option: 6; 6 + 2 × (6)3 = 6 + 2 × 216 
6 + 432 = 438
438 ≠ 1467 
Second option: 9; 9 + 2

62 Views

Question : Select the most appropriate ANTONYM of the underlined word.
The reputed officer was removed from his post as he was having a clandestine affair.

Option 1: Surreptitious

Option 2: Overt

Option 3: Amorous

Option 4: Casual

Team Careers360 25th Jan, 2024

Correct Answer: Overt


Solution : The second option is correct.

Clandestine means secret or done in a concealed or hidden manner, and overt, on the other hand, means done openly or without any attempt at concealment.

The sentence mentions the officer being removed due to a clandestine affair, indicating

2 Views

Question : Directions: In the following question, select the missing number from the given responses.

2   4 5   3
3 3 3 6 ? 6
1   2 1   6

Option 1: 5

Option 2: 2

Option 3: 3

Option 4: 1

Team Careers360 22nd Jan, 2024

Correct Answer: 3


Solution : Given:

2   4 5   3
3 3 3 6 ? 6
1   2 1   6

The pattern followed is as follows –
In the first part; 2 + 3 + 1 = 6; 4 + 3 + 2 = 9→9 – 6 = 3
In

50 Views

Question : The perpendicular distance from the centre of a circle to the chord is 20 cm. Calculate the chord's length in centimetres if the circle's diameter is 58 cm.

Option 1: 42

Option 2: 21

Option 3: 56

Option 4: 28

Team Careers360 23rd Jan, 2024

Correct Answer: 42


Solution :
Given:
Diameter, AB = $58$ cm
So, Radius = $\frac{58}{2}=29$ cm
CD is the chord.
Its distance from the centre, ON is $20$ cm.
CD = $2$ × CN
Join OC.
OC is the radius.
From $\triangle$OCN,
OC2 = ON+ CN2

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