A total of 57 sweets were distributed among 10 children such that each guRl 5 sweets and each boys 6 sweets . Find the number of girls

Dear simran
I would like to help you in this question
Answer is 3 girls .
Consider X as number of girls and Y as number of boys
And there total 10 children
Therefore X+Y=10
Now rearranging above equation as we want to know number girls, Y= 10-X

Now, total 57 sweets has been distributed among X girls and Y boys such that each girl gets 5 sweets and each boy gets 6 sweets

Therefore 5(X) + 6 (Y) = 57
Substituting Y in above equation
5X + 6 (10-X)= 57
5X + 60 -6X =57
And therefore X=3

I hope this help you understand
All the best

total sweets were 57

each girl got: 5

each boy got:6

total children:10

let number of girls be x and boys be y then

5x+6y=57 ------eq(i)

x+y=10 ---------eq(ii)

multiply 5 to eq(ii)

5x+5Y=50 -------eq(iii)

eq(i)-eq(iii)

5x+6y= 57

-5x-5y=-50

-------------------

y=7

from eq(i)

x=3

therefore, total girls are 3 and boys are 7