Question : Find the value of $\tan (50°+\theta)-\operatorname{cot}(40°-\theta)$.
Option 1: $\frac{1}{2}$
Option 2: $-1$
Option 3: $0$
Option 4: $1$
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Correct Answer: $0$
Solution :
$\tan (50°+\theta)-\cot(40°-\theta)$
We know, $\cot(90°-x)=\tan x$
$=\tan(50°+\theta)-\cot(90°-(50°+\theta))$
$=\tan(50°+\theta)-\tan(50°+\theta)$
$=0$
Hence, the correct answer is $0$.
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