Question : If $\frac{a}{b}+\frac{b}{a}=1$ and $a+b=2$, then the value of $a^3+b^3$ is:
Option 1: 0
Option 2: 3
Option 3: 1
Option 4: 2
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Correct Answer: 0
Solution :
$\frac{a}{b} + \frac{b}{a} = 1$
$⇒ \frac{(a^2 + b^2)}{(ab)} = 1$
$⇒ (a^2 + b^2) = ab$ ----(i)
$a^3 + b^3 = (a + b)(a^2 + b^2 – ab)$
Putting the value of $(a^2 + b^2)$ from equation (i),
$⇒ a^3 + b^3 = (a + b)(ab – ab)$
$= 0$
∴ The value of $a^3 + b^3$ is 0.
Hence, the correct answer is 0.
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