Question : If $3x+5y+7z=49$ and $9x+8y+21z=126,$ then what is the value of $y$?
Option 1: 4
Option 2: 2
Option 3: 3
Option 4: 5
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Correct Answer: 3
Solution :
Given: equation (1): $3x+5y+7z=49$
Given: equation (2): $9x+8y+21z=126$
Multiplying the equation (1) by 3 and subtracting equation (2) from it, we get,
$15y-8y=(3\times 49)-126$
$⇒7y=21$
$\therefore y=3$
Hence, the correct answer is 3.
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