Question : If $p=3+\frac{1}{p}$, then the value of $(p^4+\frac{1}{p^4})$ is:
Option 1: 81
Option 2: 27
Option 3: 120
Option 4: 119
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Correct Answer: 119
Solution :
Given: $p=3+\frac{1}{p}$
The algebraic identity used is $(p-\frac{1}{p})^2=p^2+\frac{1}{p^2}-2$
$(p-\frac{1}{p})=3$
On squaring both sides of the given equation, we get,
$(p-\frac{1}{p})^2=3^2$
⇒ $p^2+\frac{1}{p^2}–2=9$
⇒ $p^2+\frac{1}{p^2}=9+2$
⇒ $p^2+\frac{1}{p^2}=11$
On squaring both sides of the given equation, we get,
$(p^2+\frac{1}{p^2})^2=11^2$
⇒ $p^4+\frac{1}{p^4}+2=121$
⇒ $p^4+\frac{1}{p^4}=121–2$
⇒ $p^4+\frac{1}{p^4}=119$
Hence, the correct answer is 119.
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