Question : If $p+\frac{1}{p+2}=2$, then the value of $(p+2)^3+\frac{1}{(p+2)^3}–3$ is:
Option 1: 45
Option 2: 18
Option 3: 52
Option 4: 49
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Correct Answer: 49
Solution :
Given: $p+\frac{1}{p+2}=2$
Add 2 both sides of the above equation and we get,
$p+2+\frac{1}{p+2}=4$
Cube both sides, and use: $(x+\frac{1}{x})^3=x^3+\frac{1}{x^3}+3(x+\frac{1}{x})$
$(p+2)^3+(\frac{1}{p+2})^3=4^3–4\times 3=64–12 =52$
⇒ $(p+2)^3+\frac{1}{(p+2)^3}–3 = 52 – 3 = 49 $
Hence, the correct answer is 49.
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