Karnataka Post Graduate Common Entrance Test
Applying for PGCET with missing study certificates can be challenging but not impossible.
Hello aspirant,
The Karnataka PGCET 2024 application form will be made available on the official website by KEA. The PGCET application form can be completed online at kea.kar.nic.in by candidates. On the official website, the authorities will declare the Karnataka PGCET 2024 registration date. Prior to submitting their application, candidates
Question : Which of the following is used to view pages and navigate the World Wide Web?
Option 1: Hyperlink
Option 2: Web browser
Option 3: World Wide Web
Option 4: Joystick
Correct Answer: Web browser
Solution : The correct answer is a Web browser.
The tool used to view pages and navigate the World Wide Web is a web browser. A web browser is a software application that allows users to access, retrieve, and view information on the internet. It
Question : The value of $\frac{\frac{1}{3}+[4 \frac{3}{4}–(3 \frac{1}{6}–2 \frac{1}{3})]}{(\frac{1}{5} \text { of } \frac{1}{5} \div \frac{1}{5}) \div(\frac{1}{5} \div \frac{1}{5} \times \frac{1}{5})}$ lies between:
Option 1: 10.2 and 10.8
Option 2: 4.2 and 4.4
Option 3: 8.2 and 8.8
Option 4: 0.4 and 0.9
Correct Answer: 4.2 and 4.4
Solution : Given: $\frac{\frac{1}{3}+[4 \frac{3}{4}–(3 \frac{1}{6}–2 \frac{1}{3})]}{(\frac{1}{5} \text { of } \frac{1}{5} \div \frac{1}{5}) \div(\frac{1}{5} \div \frac{1}{5} \times \frac{1}{5})}$ $=\frac{\frac{1}{3}+[ \frac{19}{4}–(\frac{19}{6}– \frac{7}{3})]}{(\frac{1}{25} \div \frac{1}{5}) \div(\frac{1}{5} \times 5 \times \frac{1}{5})}$ $=\frac{\frac{1}{3}+[ \frac{19}{4}–(\frac{19–7\times 2}{6})]}{(\frac{1}{25} \times 5) \div(\ \frac{1}{5})}$ $=\frac{\frac{1}{3}+[ \frac{19}{4}–\frac{19–14}{6}]}{\frac{1}{5} \div\ \frac{1}{5}}$ $=\frac{\frac{1}{3}+[ \frac{19}{4}–\frac{5}{6}]}{\frac{1}{5} \times 5}$ $=\frac{\frac{1}{3}+[
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