Hello Deepak,

Considering last year's cut-off of KCET and according to your rank in KCET you cannot get admission in BVB college, Hubli. You'll neither get Computer Science and Engineering not electronic and communication engineering as the closing ranks are 5674 and 7494 respectively.

Good Luck!

Hey,

According to me you should go to the counselling, maybe you would get a better or a good college than the recent college in which you took admission. Also, if it is of no use then also you should go just to see the environment or how things work

Yes, you can apply for both MHT CET(Maharashtra CET) and KCET(Karnataka CET).

If you want to apply for MHT CET and KCET, firstly you should be the citizen of India.

Candidate applying for CET should have successfully passed the qualifying examination(10+2 or equivalent) with physics and maths as a compulsory

Hi Rajeshwari,

I can provide you the KCET 2017 and KCET 2018 Closing Ranks for CMRIT Bangalore.

These are GENERAL MERIT (GM) cutoffs. 

In 2017, after the last round-

ECE- 12,800

In 2018, after the last round-

ECE- 21,834

If you belong to a specific category, please specify it in

Nitish, it seems difficult for you to get admission CSE branch in Global Academy of Technology - [GAT] - Bangalore. This is based on your rank and previous year cutoffs. The branch closes at around 15,000 here. You can definitely get the other branches there. 

But again it depends on

Hi Rajeshwari,

You will have to provide me your category as well because there are many categories in KCET 2019.

But, I can provide you the KCET 2017 and KCET 2018 Closing Ranks of EC branch for the University of Visvesvaraya College of Engineering, Bangalore.

These are GENERAL MERIT (GM)

Hi Sakshi,

You will have to provide me your category as well because there are many categories in KCET 2019.

But, I can provide you the KCET 2017 and KCET 2018 cutoff ranks of the EC branch in SJBIT Bangalore.

These cutoffs were for 1G category candidates.

In 2017, after

Hello Rahul,

Based on the information provided by you in the query using 75% as your 12th percentage and 60 marks out of 180 your rank will be around 81,500 - 84,000. You can also use the kcet college predictor from the following link:

https://www.careers360.com/kcet-college-predictor

All the best.