Hello Aspirant,

If you belongs to Telangana, then definitely you can apply for TS LAWCET and TS EAMCET provided that you satisfy all other eligibility requirements which are discussed below :-

@TS LAWCET :-

** Only Indian national are eligible to apply if they meet the local/unreserved status for Andhra

Yes if you are from Karnataka for any other state it doesn't matter you can attempt the the TS for AP EAMCET even if you are not from the AP or Telangana States.

While applying for the EAMCET exam you need to select the other option while your filling the

Hi

You can download TS EAMCET i. e Telangana State Engineering Agriculture and Medical Common Entrance Test Sample Paper by going through the link given below

https://engineering.careers360.com/download/ts-eamcet-sample-papers-previous-years

Solving these papers will be very beneficial for you, it will help you to :-

------) know the pattern  of the examination.

------)

Hello aspirant,

TS EAMCET form with late fee of Rs. 250/- June 15, 2021.( Submission).

Application form correction dates May June 11 to 16, 2021.

For Application Form Documents Required are

examination hall ticket number. (Qualifying).

TS/AP online transaction id (to pay through TS/AP online centre)

Credit Card or Debit

Hello,

This year the rank is determined by marks scored in TS EAMCET Entrance Examination alone. The marks scored in IPE are not given any weightage. Marks scored in TS EAMCET are considered. It is quite difficult to predict the exact rank as it depends on various factors such as

Dear learner,

B pharmacy can be joined by both MPC and bipc stream here are some colleges and there cut-off for general category of tseamcet 2020.

CODE.              COLLEGE NAME.         CUTOFF'GENERAL-

1. ANWP--Anwar-uloom college of pharmacy,hyd,--- 82126
2. BNPW--bojjam narasimhulu pharmacy college of women,saidabad,hyd (bipc-18937,mpc-74112)
3. DSOP--- Deccan school of pharmacy, Nampally,hyd--- 200042
4. GPRP--G

Hey,

An equation of the form dxdy+Py=Qun where P and Qare functions ofx alone or constants, is called Bernoulli's equation. Divide both the sides by yn, we get
y−ndxdy+Py−n+1=Q Put
y−n+1=z⇒(−n+1)y−ndxdy=dxdz.
The equation reduces to 1−n1dxdz+Pz=Q⇒dxdz+(1−n)Pz=Q
Which is linear in z and can be solved in the usual manner.
So

Dear learner,

It's nice to see that your anxious about scoring maximum marks , so minimum 25% marks should be scored in ts EAMCET to qualify . So total 40 marks will be neede out of 160 to qualify

Behalf of that you need to score more , scoring more