Crack Exam
Hi Rahul,
78.73 percentile means that 78.73 students are behind you who appeared for the exam. Your approximate rank can be determined by using the following formula:
JEE Main 2019 rank= (100- NTA percentile score ) X 874469 /100
Therefore Your calculated Approximate rank is 185999.
Whether you have qualified jee mains and are eligible for jee advance or not will depend upon whether you have crossed the cutoff marks declared by NTA officially. This cutoff will be different for different categories of students. As of now, the cutoff have not been declared and reportedly will be declared after the jee mains exam in April. So better wait for official results.
Good luck
Hello Uwais,
The gate preparation for the field of chemical engineering is great,
we have a detailed article on our website for the same, please go through this article,https://www.careers360.com/chemical-engineering-course
and also, the books that you can use are:
https://engineering.careers360.com/download/ebooks/careers360-quick-guide-to-chemical-engineering
and if you have any more questions, do ask!
Hii satty,you are going to have enough time to prepare for neet as now you are in 12 only if you will work hard but my dear friend being your well wisher I would like to say that it's your 12th you should study for getting good marks in 12 as boards marks are too important,but if you can balance between your studies of school and neet preparation then it's okh otherwise you can drop your year after your school for the preparation it's upto you.Goodluck
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