Distance
Hi,
B.ed in distance mode is provided by many institutions in india. Some of which are -
Annamalai University Directorate of Distance Education
Indra gandhi open university
Andhra university
Yashwant rao chavan mukt vidyapith
Sri Venkateswara University
Tamil nadu state open university
Jamia Millia islamia- center for distance and open education.
Hello
The focal length of the lens is -12 cm.
Hello!
No need to worry for the gap. You are eligible for doing distance MBA. Here I'm listing a few top colleges to consider for distance mba:
1) Symbiosis distance mba (mat/cmat/cet/Studentsgmat/cat/those who have not appeared in any of the State Level or equivalent entrance test at State or National Level need to clear SCDL-PGDBA Entrance Test for PGDBA)
2) ignou distance mba (openmat exam)
3) nmims dustance mba (no entrance exam)
3) itm ghaziabad distance mba (no entrance exam)
5) icfai distance mba (mat/xat/sat/gate exams)
6) sikkim manipal university distance mba (45% in entrance exam conducted by university/cat/xat/atma/iift/snap/gmat/ignou/ibsat/tissnet)
Basic eligibility will be:
To have minimum 50% marks in graduation & you have to write entrance exams for admission into mba/pgdm program.
According to the question, the length is 3 √ 2
Hello Surya,
I guess your question is incomplete, as the figure is missing. The radial distance is not mentioned.
Kindly repost your question with sufficient data.
Hello Sunil,
Your question is quite simple, the answer to your problem can be obtained by using the formula,
E*2*pi*d*epsilon=lambda
where epsilon is the permitivitty of free space, and lambda is the linear charge density.
Substitute the values, as given in the question,
E=9*10^4 N/C
pi=3.14
epsilon=9 × 10 9 N m 2 C −2
and d=0.02m
Hope this Helps
Hello,
The programs offered in Dr AER Degree and PG College, Tirupati are BSc, BBA, BCom,MSc.
All are offered in regular mode only.
The college doen't have official website, so you can check out the following link for more details regarding this-
https://www.careers360.com/colleges/dr-aer-degree-and-pg-college-tirupati
Hi Candidate,
The free fall distance is s which is experiencing a force of F equal to the mass of without the body, any external force in a certain time.
Now as we have a frictional force of F/2, equals to half of the weight in the same certain time, so as Force is directly proportional to distance, hence the value of distance also get halved as the force gets halved.
Hope that you have got your answer. All The Best. Have a Good Day!!
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