hello,

greeting.

according to me, you should opt code 5 for neet examination. this is because you will completed your first year of bsc in 2019 and you are appearing for the neet in 2020. so the code 5 is best for you.

thanks.

Hey!There

First find acceleration of car from given intial velocity,final velocity and time taken by car to reach final velocity.And then find displacement covered by body using displacement- acceleration formula(S=ut+1/2at^2).

Ask if any query.

Hii,

You can check the answer to this question in the link provided.

https://learn.careers360.com/engineering/question-solve-it-the-force-of-interaction-between-two-atoms-is-given-by-where-x-is-the-distance-k-is-the-boltzman-physics-and-measurement-jee-main/

hi,

I have mentioned the colleges name below which is best if you want to pursue distance mba course along with you current work,

NMIMS Global Access School for Continuing Education

Symbiosis Centre for Distance Learning (SCDL)

IMT-Centre for Distance Learning (IMT-CDL) Ghaziabad

Indira Gandhi National Open University (IGNOU)

Sikkim

Hello,

The Best Colleges in India for Distance MBA program are:

1. Institute of Management Studies, Gaziabad

2. Narsee Monji Institute of Management Studies

3. Symbiosis Centre for Distance Learning, Pune

4. Indira Gandhi National Open University, Delhi

5. Sikkim Manipal University

6. Annamalai University

7. Amity University

8. ICFAI

hi,

yes you are eligible for llb degree  of 3 years. the eligibility criteria for  llb is you need to pass graduation degree in any discipline from a recognized board of education. marks criteria of graduation can be different for different institutions.

some top llb entrance test:

du llb entrance

Hello,

yes there is a difference. Firstly, you won't be able to interact with teacher face to face. You have to understand things by yourself and even if you ask there are possibilities  you won't understand concepts that easily.

You won't be physically present and it will be a online

Hii,

The answer for this will be y^2 = 4(b−a)(x−a) .

we'll get this equation after undertaking the following steps:

Given, Vertex A is (a,0)

Focus is (b,0)

Distance between vertex and focus AS = b−a=A (say)

So, the equation of parabola with vertex at (a,0) is
(y−0)^2 = 4A(x−a)(y−0)^2