With a 9 lakh rank in JEE Main and being a female candidate from Uttar Pradesh (MJPRU), it’s difficult to get admission through JEE Main in top government colleges. However, some private colleges under MJPRU may still offer you admission, especially in non-core branches like IT, civil, or electrical. Also,

Hi aspirant,

KCCET uses a 50:50 weightage ratio to determine student rankings, with 50% of your rank based on your board exam marks and 50% based on your KCET score.

You can calculate your score yourself, but for a more precise rank, it is recommended to visit the Career 360

With a 1.6 lakh JEE Mains rank and being a girl candidate, you can get admission in some NITs (like NIT Mizoram, Meghalaya, Nagaland) in lower branches like Civil or Chemical, especially if you belong to a reserved category or have home state quota. Also, many GFTIs and good state

With a 44,000 OBC rank in JEE Mains, getting a free seat (meaning no tuition fee under fee waiver or low fees) in top NITs or IIITs for CSE or ECE is tough. But you have good chances in lower branches like Civil, Mechanical, or Metallurgy in newer NITs like

With a 600,000 CRL and 850,000 EWS rank in JEE Mains 2025 , getting into top colleges like YMCA or similar ones is unlikely through JEE counseling . However, you may still have chances through:

• State Quota : Try state-level counseling in Haryana for better chances.

• Private Colleges : Explore

With a JEE Main All India Rank of 3,11,876 and 78.99 percentile in the OBC category, getting CSE in top NITs or IIITs is not possible. But you still have chances in private colleges or some state-level government colleges with lower cutoffs. Some newer or less competitive colleges might offer

It's understandable that you're curious about your chances of getting into the Computer Science Engineering (CSE) program at Madan Mohan Malaviya University of Technology (MMMUT) Gorakhpur with your JEE Main All India Rank of 311876 and an OBC category percentile of 78.99. Let's break it down in a simple way.

Hi aspirant,

KCCET uses a 50:50 weightage ratio to determine student rankings, with 50% of your rank based on your board exam marks and 50% based on your KCET score.

You can calculate your score yourself, but for a more precise rank, it is recommended to visit the Career 360

Hi aspirant,

KCCET uses a 50:50 weightage ratio to determine student rankings, with 50% of your rank based on your board exam marks and 50% based on your KCET score.

You can calculate your score yourself, but for a more precise rank, it is recommended to visit the Career 360