Rank
With a GATE 2025 CS score of 406 and AIR ~14,000 , securing M.Tech in Cybersecurity at IITs is unlikely, as they typically require scores above 750. For PSU recruitment , most companies have cutoffs ranging from 750 to 850 , making opportunities limited.
NIT Patna : In
To predict the colleges for your JEE Main rank , you can use the JEE Main College Predictor tool available on platforms like Careers360 .
Here's how it works:
Input your JEE Main rank and other details like category and preferred branch.
The predictor will list colleges that match your
With a JEE Mains rank of 388385, securing a seat in a well-regarded college for Computer Science B.Tech will be challenging, especially if you are aiming for top National Institutes of Technology (NITs) or Indian Institutes of Information Technology (IIITs). Generally, these premier institutions have closing ranks much lower than
ou can use the KCET Rank Predictor available on platforms like Careers360 to estimate your rank based on your marks. Here’s how you can use it:
Visit the Careers360 KCET Rank Predictor page.
Enter your KCET marks , category , and other required details.
The tool will predict your rank
With a JEE Main rank of 90,000 , here are some options:
GFTIs :
NIT Goa : Civil Engineering (Rank: ~89,400)
NIT Silchar : Civil Engineering (Rank: ~85,200)
NIT Srinagar : IT (Rank: ~94,791)
Private Colleges :
Amity University (Noida)
Bharati Vidyapeeth College of Engineering
Participate in
The rank in KCET and board exams depends on various factors like the overall performance of candidates, the difficulty level of the exams, and the distribution of marks in that specific year. For KCET, ranks are generally calculated based on your marks compared to the total number of candidates and
To estimate your KCET 2025 rank:
- KCET score: 55 out of 180
- Board score: 215 out of 300 (≈ 71.7%)
KCET rank is calculated using 50% weight from KCET marks and 50% from PCM board marks.
Approx normalized marks:
- KCET: (55/180) × 100 ≈ 30.56%
- Board:
KCET marks (out of 180) = 74 → (74/180) × 100 = 41.11
PUC average (you got ~92.67%)
Final normalized score = (41.11 + 92.67) / 2 = 66.89
a 66.89 composite score , here’s a rough estimate of your PCB rank (for general category including OBC 3A):
Expected Rank
Hello,
Based on your SC category rank of 7,400 in JEE Main 2025, it might be difficult to get Mechanical Engineering at IIEST Shibpur . Last year, the closing rank for SC candidates from other states in Mechanical Engineering was around 6,706.
However, you can still consider other good colleges
Hi aspirant,
KCCET uses a 50:50 weightage ratio to determine student rankings, with 50% of your rank based on your board exam marks and 50% based on your KCET score.
You can calculate your score yourself, but for a more precise rank, it is recommended to visit the Career 360
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