Score
Your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be 58197. It’s difficult to tell exact qualifying marks for jee advanced eligibility but if you are getting more than 85 percentile score then you have decent chances to qualify for
Your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be 272956. You can use our College predictor to predict your colleges: https://engineering.careers360.com/jee-main-college-predictor?
Hello Aspirant,
The exact prediction would be difficult to provide you the information regarding admission possibilities. As per the previous year cutoff this score seems not enough to get a seat in NITs, IIITs & GFTIs for CSE or other branches.
You can try for the state level counselling. To
Hello,
To check your score in different sections and total score, you have to download your score card from the official NTA webpage by providing your credential details. These are the normalized scores from all the sessions conducted. The percentile scores are from the candidate respective session only in which
It's difficult to tell you the exact about the qualifying cutoff & admission cutoff. This score seems enough to qualify the exam as OBC category but chances seems less to get NITs, IIITs & GFTIs Etc. You can go for state level counselling like Pinjab , Haryana, MP
Hello
The result of JEE Main 2020 January exam has been released result is available in the form of score card containing four NTA scores in the form of percentile for Physics, Chemistry and Mathematics and total score. So, 79.584 is the percentile in JEE Main exam.
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