which college conduct acting classes
Hello Aspirant,
Hope you are doing great. Here are some famous colleges and schools for acting courses:
- Anupam Kher’s Actor Prepares the School for Actors
- Indian Academy of Dramatic Arts
- NSD - National School of Drama, Delhi
- Film and Television Institute of India (FTII)Erandwana, Pune
- KIIT - Kalinga Institute of Industrial TechnologyBhubaneswar
- A.J.K. Mass Communication Research CentreOkhla, Delhi
- Punjabi University, Patiala
- Institute of Creative Excellence, New Delhi
- Institute of Creative Excellence, Kolkata
- Livewires- The Media Institute
You can refer the below link for more details:
https://www.careers360.com/courses/diploma-in-acting
ALL THE BEST
two force is numerically equal to 10 lines are acting as shown in the figure and then the resultant of these two vectors
Hi!!!
Hope you are doing well.
The resultant of these two forces is given as
F1=F2=10 dynes.
Angle between F1&F2 = (180-60) = 120.
Resultant F:
Mod(F) = square root(F1^2+F2^2+2F1F2cos 120)
= square root(10^2+10^2+2(10)(10)(-0.5))
= 10
Therefore, the resultant force has also the magnitude of 10 dynes.
Hope you are clear now. Feel free to ask if you have any other queries. All The Best!!!
ba for acting as degree after inter
Hello aspirant,
You must have passed intermediate or 12 th standard from a recognised Board or College.
Best Colleges in India offering BA Acting course are given below along with their fees structure.
- Rashtrasant Tukadoji Maharaj Nagpur University, Nagpur- Fees : Rs. 15,000 per annum
- Amity University, Noida- Fees: Rs. 1,70,000 per annum
- Whistling Woods International, Mumbai- Fees: Rs. 7,00,000 per annum
- Sharada University, Greater Noida - Fees: Rs. 80,000 per annum
- SGT University, Gurgaon - Fees: Rs. 1,62,500
For more information go through below mentioned link.
May this information was useful to you.
Good Luck!!
A body of weight 300 N is lying on a rough horizontal plane having a coefficient of frict ion as 0.3. What would be the magnitude of the force, which can move the body, while acting at an angle of 25 with the horizontal? a)67 N b)77 N c)87 N d)97 N
Hi there,
Answer is C -87 N
as it is given weight=300 N
u=0.3
Let p is force and force of friction is f
resolving forces horizontally
F=p cos 25
=p×0.9063
Vertically it is R= W-p sin 25 degree
R= 300-P × 0.4226
Force of friction
0.0963×p=uR= 0.3×(300-0.4226P)
=90-0.1268p
=0.9063p+0.1268p= 90
(1.0331)p=90
P=87.1 N
force acting on a moving charge of magnet
Hi there,
Moving electric charge produces magnetic field. In other words magnetic field is created when an electrical charge in motion.
Most basic form of force is that which magnetic field exerts on moving charges. Direction of magnetic force on moving charge follows right hand rule and it is perpendicular to plane formed by V and B.
Magnitide of force is proportional to q,v,b and the sine angle between v and b .
Hope it helps you
Good luck!
which career and subject should i keep as a backup subject if i want to go for acting?
Hello!
You can pursue degree in performing art and drama which offers by the few of schools of arts. There is no requirement of a degree course to become an actor or actress.
BA in art and drama takes the duration of three years as the graduation degree programme.