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i scored 120/120 in chemistry and 103/120 in physics and 100/100 in maths in my class 12 higher secondary examination and according to the answer key keam 2020 i got 255/960 what will my rank in keam 2020

Shebinsha P K 25th Aug, 2020

Hi there,

KEAM rank is calculated based on your entrance marks as well as your class 12 PCM marks. Since you got excellent PCM marks and a decent entrance marks, you will get a good KEAM rank.

Based on your given scores, you can expect a KEAM rank of around

102 Views

bhu entrence exam2008 answer key

Sreeja Siva 8th Sep, 2020

Hi,

The previous year answer  keys of the entrance exam is available on https://bhustudentclub.in/2017/07/24/download-10-years-bhu-uet-previous-year-question-papers/ you can check in the website to find out whether the 2008 answer key is available or not but it's paid one. You haven't specified the subject you are looking for. But there are some sites

202 Views

hi,I got 122 marks in jee main according to nta answer key and I belong to ews category will I get mnnit cs by home state and ews qouta ,please guide me

Suvangi Pathy 8th Sep, 2020
Hello aspirant,which colleges you can get into can be predicted only by the final percentile you will get and your AIR and EWS rank.Seeing the general statistics of past years ,122 marks is not enough for you to get CS in MNNIT eventhough you have Home State quota and EWS
927 Views

I want Gujarati language question paper and answer key in aibe exam 2012 to 2019

LAKUM P 18th Sep, 2021

6uuubgd the hi res sir please find attached the hi res sir please find

53 Views

answer of Q2 in Maths answer key (shift 2) by Careers360 is wrong ....it should be 5 instead of 4 .. in last 2nd step 2(n-1)(n-1+1)/2 =20

Shruti Smaranika 21st Oct, 2020

Hello aspirant,

Sorry for the wrong answer issued earlier. The answer will be 5 instead of 4.

The question is:

{2(n-1)*(n+1-1)}/2= 20

The answer is done as follows-

=> (n-1)*(n-1+1)= 20

=> n(n-1)= 20

=> n^2-n-20= 0

=> n^2-5n+4n-20= 0

=> (n^2-5n)*(4n-20)= 0

=> n(n-5)*4(n-5)= 0

=> (n+4)*(n-5)= 0

=>

285 Views

we want the previous year paper of gujarat pgcet for pharmacy and computer science branch with answer key please send us the link and when the gujarat pgcet 2020 forms will be started

swetaasnigdhha 21st Jul, 2020
Hii,

You can find the question papers in the given link

https://www.oldquestionpapers.net/pgcet-question-papers-answers-previous-year-old-papers


The dates for the exam in 2020 are still not declared officially but the tentative dates are around 22nd July to 31st July for form filling. But during this COVID pandemic it might get more delayed.

Hope my
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