WHETHER U WRITTEN NATA EXAM .

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Hello Srikanth,

here the top colleges for architecture in Hyderabad:

PRIVATE:

1.International Institute of Information Technology, Hyderabad.

2.ICFAI Foundation for higher education, Hyderabad

3.CSI Institute of Technology, Secunderabad

4. Sri Venkateswara college of Architecture, Hyderabad

etc..

PUBLIC:

1. jawaharlal nehru architecture and fime arts university school of planning and architecture,

Hello Sarthak,
The eligibility criteria for admission in Piloo Mody College of Architecture,Cuttack is to pass the 12th exam with atleast 50% aggregate marks and also 50% minimum aggregate marks in PCM and just to qualify the JEE Main exam or NATA. Your percentile looks promising enough to get you

Hello there,

Hope you’re having a nice day.

I would like to inform you that 94% is much better if you are looking for government colleges in India. I am providing you a list of colleges where you can expect to get admission with a fairly good percentage of admission.

Hey aspirant!

National Testing Agency (NTA) has already declared the results of JEE Main 2020 Paper 2 and you can check your results on the official website and hence you don't need to see the percentile and rank predictor as you can know your actual and official results now by

Hello Sameer,

According to the previous data ,you have more changes of getting seat in the NITs. you can check the college that you are eligible  by using the college predictor which link has been given below and also  you have a good percentile to get the seat in good

Hello,

these are top architecture colleges in Hyderabad

• ICFAI Foundation for Higher education
• Jawaharlal Nehru architecture and fine arts university school of planning and architecture
• Malla Reddy Engineering college for women
• CSI Institute of Technology
• Sri venkateshwara college of Architecture

https://engineering.careers360.com/colleges/list-of-b-arch-colleges-in-telangana

you can refer this link for more

Hope it

Rank in JEE Main Paper 2 can be calculated by the formula:

Rank = (100-percentile)*(No. of students appeared for the examination)/100

As the no. of students appeared for Paper 2 are 112679, your rank will be around 1600. However as the no. of students in April changes, your rank will