B.Arch
Hi dear,
You have scored 98.89 percentile in JEE main paper 2 that means your rank should be around 1250. You can also calculate your rank as
Rank=(100-your percentile)×112679÷100
With this rank you have a chance to get NITs. You can check your college here
https://www.google.co.in/url?q=https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning&sa=U&ved=2ahUKEwjD_emnj67nAhVd8XMBHduMBNUQFjADegQIBxAB&usg=AOvVaw0j_xG9vFSjdcJuR_mJttH0
Hope it helps.
Hello ,
For JEE mains paper 2 , you must get more than 75 percentile for having chance to get admission in any NITs . For particularly , NIT trichy click on the given link below to see the cut off last year so as to get idea about how
Hello!
To qualify for B.Arch in IIT Kharagpur you have to write both JEE Main and JEE Advanced.
Only Admission Seeker who have qualified the JEE Mains are allowed to sit for JEE Advanced. If a student wants to join B.Arch in IIT Kharagpur they first have to clear JEE
Hello Aspirant
With this percentile in JEE MAINS PAPER 2,your expected rank should be 2478 and its a good chance for you that you will get some NITs and also it depends on your category,if you belong to reserved category,there are some chances that you will get top NITs. But
Vikas, you can calculate your expected JEE Mains paper 2 rank for the January session using the following formula:
(100-your total percentile) x 112679/100
So with 97.69 percentile, your rank would be around 2602.
Also, if the number of students increases to 1.5 lakh in the April session, the formula
Hello dear student !
DCRUST university is located in murthal, Haryana (comes in Delhi-NCR region) and offer various courses for the students. It also provides hostel facilities. The fee structure of DCRUST murthal for B. Arch course in OBC category is INR 47,050 per annum.
Hope this will help you
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