B.E /B.Tech
Happy Guru Purnima to you as well!
Since you're in a situation involving syllabus changes, it's best to confirm directly with your university or college administration. Here's what you can do:
Here are some possibilities to consider:
Clearing KTs: Regardless of the syllabus transition, clearing your KTs is crucial. It ensures you have the necessary foundation for higher semesters.
By contacting your university and focusing on clearing your KTs, you'll be in a better position to smoothly transition to the next year, be it the old or the new NEP syllabus.
hope this helps you!!
Hello there,
To know about the colleges you might qualify based on your rank, visit the link below. It includes a college predictor which matches your rank with potential colleges.
KCET College Predictor
https://www.careers360.com/kcet-college-predictor?
To get answers on more queries visit, www.careers360.com
With an SC category rank of 41,715 and a CRL rank of 570,173 in JEE Main, getting into NITs or top-tier IITs for B.E./B.Tech may be challenging. However, you might find options in state engineering colleges in Maharashtra, as they often have seats reserved for SC candidates with lower cutoff requirements compared to NITs. Look into state-level entrance options like MHT CET or other reserved category seats in Maharashtra’s government and private engineering colleges for better chances.
Greetings!
LLB, or Bachelor of Laws, is a popular undergraduate program that typically spans 3 years. It's designed for those who wish to pursue a career in law. To be eligible, you usually need a bachelor's degree in any field with a minimum of 45% marks. The course covers various aspects of law across 6 semesters, providing a comprehensive understanding of legal principles and systems. LLB opens doors to diverse career paths in law, such as becoming a lawyer, legal consultant, or working in corporate legal departments. It's a foundational step for those aiming to make a mark in the legal domain, and the eligibility criteria ensure a basic academic background for prospective law students.
Hello,
Yes definitely, Here is a summary of the VTU Academic Calendar for the 1st Sem MBA in 2023-24-
- the first Semester begins- 12th February 2024
- Classes start from-12th February 2024
- Last day of the semester- 25th May 2024
Hope this helps you,
Thank you
https://www.careers360.com/courses/mba-master-of-business-administration
Question : The Punjab crisis in the 1980s involved conflicts between:
Option 1: Hindus and Muslims
Option 2: Sikhs and the central government
Option 3: India and Pakistan
Option 4: Urban and rural populations
Correct Answer: Sikhs and the central government
Solution : Correct Option: Option 2 Explanation: The Punjab crisis in the 1980s involved conflicts between Sikhs, who were demanding greater autonomy and recognition, and the central government.
Question : Directions: In the following question, select the related number from the given alternatives. 7 : 32 :: 35 : ?
Option 1: 144
Option 2: 156
Option 3: 160
Option 4: 172
Correct Answer: 172
Solution : Given: 7 : 32 :: 35 : ?
Like, 7 : 32→(7 × 5) – 3 = 35 – 3 = 32 Similarly, for 35 : ?→(35 × 5) – 3 = 175 – 3 = 172
So, 35 is related to 172. Hence, the fourth option is correct.
Question : A certain distance is covered by a cyclist at a certain speed. If a jogger covers half the distance in double the time, the ratio of the speed of the jogger to that of the cyclist is:
Option 1: $1:4$
Option 2: $4:1$
Option 3: $1:2$
Option 4: $2:1$
Correct Answer: $1:4$
Solution : Given: A certain distance is covered by a cyclist at a certain speed. If a jogger covers half the distance in double the time. We know the formula, $\text{Speed}=\frac{\text{Distance}}{\text{Time}}$ Let the cyclist travel at $x$ km/h and the distance to be covered takes $y$ hours. So, the cyclist covered $xy$ km. Jogger's distance travelled is $\frac{xy}{2}$ km. The time is $2y$ hours. The ratio of the speed of the jogger to that of the cyclist is $\frac{xy}{2\times 2y}:x$ or $1:4$ Hence, the correct answer is $1:4$
Question : If $\frac{1}{2} $ is added to a number and the sum is multiplied by 3, the result is 21. Then the number is:
Option 1: 6.5
Option 2: 5.5
Option 3: 4.5
Option 4: –6.5
Correct Answer: 6.5
Solution : Let the number be $x$. According to the question, $(x + \frac{1}{2})\times 3=21$ ⇒ $(x + \frac{1}{2}) =\frac{21}{3}=7$ ⇒ $x =7- \frac{1}{2}$ $\therefore x =6.5$ Hence, the correct answer is 6.5.
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