Hello Mudit Singh, with 13131 rank in UPSEE, it is difficult to get admission in the Bundelkhand university, Jhansi for the Bachelor of technology or for engineering course in CSE. As the cut-off for this college for general category students are very high and the admission in this college closes

Hello Deboanjali, thanks for your query.

With this rank, you can get a seat in this university but you may have to wait till last round of counselling. Visit the following link to know more about the rank required for getting a seat in this uninversity:

https://engineering.careers360.com/articles/upsee-cutoff

Hi Nishant,

I can provide you UPSEE 2018 Opening Ranks (OR) and Closing Ranks (CR) of Bundelkhand University, Jhansi.

These cutoffs were for the Biotechnology Engineering branch, so you can get a clear idea.

In 2018, after Round 3-

OR- 158 and CR- 1,396 (General)

OR- 2,055 and CR- 6,523

Dear aspirant,

I'm providing you the perfect link in which you will get each and every information regarding the previous year cutoff or opening and closing rank of various colleges under AKTU for all branches . Just go through this link and all your doubts will be cleared, I'm sure.

Hey,

Congratulations on your rank, yes there are chances that you might get this university.

Even if you belong general category your rank is pretty good to get you a seat in the university.

You can go through our link given below where you can find the closing rank for

Hey manas!  

As you are concern with neet eligibility 

Some criteria for eligibility are done 12th with science having 60% marks from recognised board. 

You must be of 17 years for getting admission 

And at last according to cbse guidelines the cut off and score card will play a vital

Hey there, 

As per your query I would like to tell you that bundelkhand University is good for Bba tourism. it's total fee about 57.15 thousands. 

It is three full time undergraduate degree course. 

Total available seat - 50.

Eligibility criteria - The candidate should not. be passed 10+2 from