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Hello sir/mam,
You have not mentioned if the candidate come under NCL or CL. If it is CL then she is considered as general category candidate. As said with 189 marks her overall percentile is expected to be in between 99.49 - 99.69 and her overall rank will be in
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Hello aspirant,
Sorry for the wrong answer issued earlier. The answer will be 5 instead of 4.
The question is:
{2(n-1)*(n+1-1)}/2= 20
The answer is done as follows-
=> (n-1)*(n-1+1)= 20
=> n(n-1)= 20
=> n^2-n-20= 0
=> n^2-5n+4n-20= 0
=> (n^2-5n)*(4n-20)= 0
=> n(n-5)*4(n-5)= 0
=> (n+4)*(n-5)= 0
=>
Hello mam, happy to hear this from you! I will share the details for joining the team. You kindly go through it and register yourself. Once check the eligibility criteria because I remember it saying only UG or PG students. Registration Link - t.ly/B16f . Kindly use my referral code
I am sorry for the inconvenience or the problem you faced. Please mention your rank in the comment below, i will try my level best to help you.
Also mention your reservation category as there are various reservation category in the KCET exam. Also mention the Rural or Karnataka part.
Dear student, there is a legal dispute between Saraswati charitable trust and Indian Union. The digital signature of Chetan Prakash was not verified duely. This is the first reason behind the dispute. Saraswati charitable trust off Lucknow applied to the ministry of health for in medical college in the name
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hi,
you may follow the below link to know about e books of careers360,
https://university.careers360.com/download/ebooks
I have mentioned some of the books name for msc entrance exam of forensic science,
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