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1st PUC chemistry modelquestion paper and key answer download link

Vivek Kumar 26th Feb, 2026

Dear Student,

You can download 1st PUC Chemistry model question paper with key answers here: Karnataka Board 1st PUC Model Question Paper 2026 (All Subjects)

Hope this helps you.

2 Views

What we do to find the no. of particles

Ritika Jonwal 9th Feb, 2026

Hi Hanifa Balaghie,

Number of  particles = Number of moles x 6.022x10(23)

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I want chemistry question bank 2026 2nd puc

Ranjeeta 27th Feb, 2026

Hi, please specify which exam question bank you are asking for.

3 Views

Mock test chapter wise chemistry

Ujjwal Kirti 27th Feb, 2026

Could you please clarify your question by mentioning your class, board, or the specific exam you are preparing for, as chapter-wise Chemistry mock tests vary for Class 11, Class 12, NEET , JEE Mains , or different state boards

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I need physical, chemistry and biology important NEET based questions in class 12

Saumya Singh 1st Mar, 2026

Hi,

For chapter-wise important questions and mock practice, you can refer to the official NEET section on Careers360:

NEET Preparation Tips – https://medicine.careers360.com/articles/neet-preparation-tips

NEET Chapter-wise Weightage –

https://medicine.careers360.com/articles/neet-chapter-wise-weightage

NEET Sample Papers –

https://medicine.careers360.com/articles/neet-sample-paper

NEET Previous Year Question Papers – https://medicine.careers360.com/articles/neet-question-paper

These resources provide structured practice, important questions, and detailed solutions

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Weightage of plusone Chemistry

Hi !

The weightage of chemistry of Plus one Chemistry is between 60 - 80.

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JEE mains 2026 formulas and short notes maths physics and chemistry

Labhanshi Kaim 27th Feb, 2026

For JEE Mains 2026 formulas and short notes for Physics, Maths, and Chemistry you can chekc the link below:

https://engineering.careers360.com/articles/jee-main-formulas

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the mass of 1.2 moles of H2O is

Ritika Jonwal 9th Feb, 2026

Hi Deepthi rajesh,

Molar mass of $\mathrm{H}_2 \mathrm{O}$

$$
\begin{aligned}
& =2 \times 1+16=18 \mathrm{~g} / \mathrm{mol} \\
& \text { Mass }=\text { moles } \text { × } \text { molar mass } \\
& =1.2 \times 18
\end{aligned}
$$

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