Hello Aspirant,

As you haven't mention the university in which you are seeking admission. If you share me the university name I will assist you better.

Good luck

Dear Amol, your 12th aggregate in Physics, Chemistry and Biology is 44%. But if you belong to General Category, the required minimum aggregate is 50%. You should have passed your 12th and then score the minimum required aggregate in Physics, Chemistry and Biology. But with 44%, unfortunately you do not

First of all Congratulating you on your nice decision to be a researcher, secondly I would like to tell you that don't let anybody else decide your future. If you are enough confident in your ideas and aims, just do it, don't think too much, because confidence is assuredness of

Hello Alok!

I am giving the solution for this question below.

We have, 2a+ b--->c

Rate=(-1/2)(d[a]/dt) = (-d[b]/dt)

So, (d[b]/dt)= (1/2)×0.04 = 0.02M/s

If V is doubled, c is halved, so:-

Rate= (1/4)×(d[a]/dt)= (1/2)(d[b]/dt)= 0.02/2 = 0.01M/s

So, the required rate of reaction is 0.01M/s.

Hope you are clear!

Hello,

Himalayan Garhwal University is a private university, approved by UGC, so definitely you can apply for government jobs as well as private jobs.

It offers various courses such such as Bachelor's Degree Programs, Master's Degree Programs and other diploma and post graduate diploma courses as well.

You can also

Dear students,

Up-and-comers probably passed Diploma in Engineering and Technology and verified at least 50 % total imprints (for General class) and at any rate 45% total imprints (for saved/in reverse classification/Persons with Disability) having a place with Maharashtra State as it were.

Top Engineering Colleges In India

• Indian Institute

Hello Eshi

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