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43 Views

Ive passed 10th finals from cbse with 95.20%, am i eligible for this scholarship??

Kulrajbir Singh Sandhu 28th Apr, 2019
Hi Sana
The percentage you have passed with is really good and after getting this percenetage you are eligible for any type of scholarships.
As you haven't mentioned it you should check the requirements of the scholarship amd apply before dealine.
Good Luck !!!
125 Views

Can I get admission in narsee monjee law college Mumbai with 82 percent in 12th and 9.8 cgpa in 10th and 80 number in clat

Amita Marotkar 3rd Jun, 2019

Hello Swarit

The eligibility for Narsee Monjee Law college, you must have passed 10+2 with minimum 50% aggregate marks and your age should be less than 25 years.

For BALLB and BBALLB the selection is done based off of CLAT score. You should apply online with all the details and

6037 Views

sir, i have lost my original 10th class marksheet. but i have a duplicate certificate. is this valid for certificate verification?

ag 24th Apr, 2019

Hello Bashna,

Duplicate certificate is given as a backup option in time of emergency.But, apply for the original marksheet too.You will get the original marksheet in a week.If you are planning to apply for any job or course then inform them in advance regarding this.So it wont create any problem.

139 Views

What was the best college after 10th class in AP ?

Hi Sai,

Narayana and Sri Chaitanya Junior colleges have been the best colleges after 10th class. They are still the best because of the experience they have in coaching students over the years. The papers they set for competitive exams is well planned and in-line with actual paper.

66 Views

What if I fall in English paper in 12 gseb hsc

Harshita 26th Apr, 2019

Hello dear...First of all be positive in life. Negative thoughts leads to negativity. Now..  worse come to worst If you fail examination you can appear in compartment / Supplementary exam conducted by Gujrat Secondary and Higher Secondary Education Board. Supplementary exam is supposed to be organized in the month of

70 Views

My name u.basavaraj as per 10th markcard but in next admitcard 2019 is u.basavaaj iam able to write next exam or not

Preetham 24th Apr, 2019

Hello aspirant.

You need to fill your name exactly as per class 10 marks card. Time will be given for correction  ,if you havent made it , now nothing can be done. 

As already admit card have been released, now there is no possible way to change your name in

55 Views

My name u.basavaraj as per 10th markcard but in neet admitcard 2019 is u.basavaaj tell me i will able to write next exam or not

Ronit Jain 24th Apr, 2019

You will still be able to write the exam and go for counselling after the results are out.

If you wrote the correct name while filling out the application form and the mistake was on NTA's part then you can mail your query to them at neetug-nta@nic.in and get it

156 Views

Ive changed school after class 10; will I need to provide transfer certificate for changing school in class 10 during neet counselling?

priyaankasarkar Student Expert 24th Apr, 2019
Dear Nilabh, it isnt necessary to submit yourn10th transfer certificate. The details of the Institution where ypu completed your 10th from are important than where you studied before your 10th. In this context, we shall give you the list of the documents that you need to carry along with you
77 Views

I passed my hsc with 63% and want to go for bsc statistics. Suggest me some colleges in mumbai university

Divyyanaa Hazarika 3rd Jun, 2019

Hello Aspirant,

It seems like you are interested in pursuing your undergraduate degree in Statistics. It has ample amount of scope in India, especially in the Government sector and thus is a much sought after course. Here is a list of colleges under Mumbai University and a few based in

315 Views

(X+Y) whole square +(Y+Z)whole square +(Z+X)whole square when X+Y+Z=2 and XY +YZ+ ZX= 1

Aaryan Sood 24th Apr, 2019

Hey Aaditya,

Here’s the solution to the asked problem:-

(X+Y)^2 = X^2 + Y^2 +2XY

(Y+X)^2 = Y^2 + Z^2 + 2YZ

(Z+X)^2 = Z^2 + X^2 +2ZX

(X+Y+Z)^2 = X^2 + Y^2 + Z^2 + 2(XY + YZ + ZX)

Use the above equations to calculate the value. 4th

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