Hello there,

The formula to calculate centripetal acceleration from radius of circle and speed of the particle is:

centripetal acceleration = [(speed) ^2]/radius

                                   = (15*15)/2

                                   =225/2

                                   =112.5  m/s²

Hope this helps.

Hello Padmakar!

We know that, distance = speed*time

So, d = 50*40 = 2000m

d = 2*3.14*r (circumference of the circle)

=> 2000=2*3.14*r

On calculating, r = 318.47 m

In this case, required acceleration will be centripetal acceleration.

So, a = (v*v)/r

        a = (50*50)/318.47

        a = 7.85m/s^2

Hope this

Hello

The syllabus for CTSE 2019 for Engineering aspirants is as follows:

Physics: Physics and Measurement, Kinematics, Laws of Motion
Chemistry: Some basic concepts in chemistry, Atomic Structure, Classification of Elements and Periodic table
Mathematics: Sets, Relations, and Functions, Complex numbers and quadratic equations, Permutation and Combination

Date of the

Hey Arpit

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Yes you can do it. Have faith in yourself .See physics can only be tackled ny regular practice.Number of formulae are limited and only the values or the wording of the questions get twisted each year.Be thorough with NCERT formulae which are a basic fundamental which cannot be overlooked.In Physics