Hello Padmakar!

We know that, distance = speed*time

So, d = 50*40 = 2000m

d = 2*3.14*r (circumference of the circle)

=> 2000=2*3.14*r

On calculating, r = 318.47 m

In this case, required acceleration will be centripetal acceleration.

So, a = (v*v)/r

        a = (50*50)/318.47

        a = 7.85m/s^2

Hope this

Hello

The syllabus for CTSE 2019 for Engineering aspirants is as follows:

Physics: Physics and Measurement, Kinematics, Laws of Motion
Chemistry: Some basic concepts in chemistry, Atomic Structure, Classification of Elements and Periodic table
Mathematics: Sets, Relations, and Functions, Complex numbers and quadratic equations, Permutation and Combination

Date of the

Hey Arpit

There are many companies that come to the campus for placements like as Reliance, Hitachi, etc. Reliance offered about 6 lacs per annum on an average, and Hitachi offered a package of 3 lacs per annum. This college also has a training and placement cell to work on.

Dear student, the Common Law Admission Test will have questions from as many as five subjects including Elementary Mathematics, English, General Knowledge and Current Affairs, Legal Aptitude and Logical Reasoning. The most preferred books by CLAT students are:

1. Word Power Made Easy by Norman Lewis

2. English is Easy by

Yes you can do it. Have faith in yourself .See physics can only be tackled ny regular practice.Number of formulae are limited and only the values or the wording of the questions get twisted each year.Be thorough with NCERT formulae which are a basic fundamental which cannot be overlooked.In Physics

Hello Aspirant,

Go through well with NCERT books to clear your basic concepts. As you told you are in class 12th, You need to devide the time properly for your boards & JEE Main Exam. With the correct preparation strategy, you can achieve the results that you want in both