hi,

see if you have taken science stream, it is mandatory to take physics, chemistry and mathematics and in fourth subject you can take biology/ statistics / computer science etc.

if your school do not offer computer science then you need to take another subjects from the given options, however

Hello!

Since you have a very good result in academics, and with 72% in mains, there might be a chance that you wont get any iits and nits . But yes since you have 95% in +2, you can easily get admission in Delhi universities.  Moreover you can clear other

Dear Aspirants ,

If you are faced problem to find out which group in computer science you are then you must go through your Batch coordinator or course coordinator because they have full list of student like which student in which group or you can login by your user id

Hello Sargun !

The cutoff score for CSE , for Veermata Jijabai Technological Institute - VJTI Mumbai is 181 for General category  and for COEP - College of Engineering, Pune cutoff score is  179 for General Category.

Hope it helps !

hi,

see if you have passed 12th course then you can directly join in b.tech program, however no all diploma college has btech course , however since you have interest in robotics, you should know that only a few institute in india has btech robotics course, since robotics comes under

I would recommend you to go in for Chandigarh University. The college not just gives elite foundation and learning assets to its understudies, however it likewise gives a lot of chances to understudies to succeed in sports and extracurricular.

Scholastically speaking, Chandigarh University has an interesting and uplifting scholarly model

Hello,

You have to do UG and PG Computer Science Engineering. If you have done it then you can apply for PhD. There is also provision of Direct PhD which can be done after UG i.e. bachelor's course. It is good  for your career if you do it in top

Hello,

If we calculate your expected rank by the formula (100-your total percentile)*869010/100 it is going to be around 141040.Where 869010 is the total count of candidates who appeared in January session.Your category rank is expected to be in between 8000-10000

In 2019 the cut off for admission in MNIT,

Hello,

as per the details given by you,

your total  marks :- 650

your score :- 379, then your percentage will be 58.30%.

To measure your percentage, formula used is :- (your score/ total mark) *100

You will get mark sheet and there your all details will be mentioned. percentage