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199 Views

I got 90.27 in Jee main can I get admission in amrita school of engineering in computer science. at amritapuri

AYAN MULLA 9th Feb, 2020

HELLO SURAJ
Congratulations for your result and qualifying JEE mains.
since it is very difficult to predict the exact rank but we do have a backup we have a formula to calculate the expected rank that is (100 – Total percentile) x 869010/100.So according to formula your expected rank for

91 Views

hi sir jee 2020 score 96.5141161my home state Karnataka. sc category wide computer science course I want nit Suratkal please send me answer

Rahul Student Expert 9th Feb, 2020
Hello aspirant,

Based on your percentile score your rank will be around 30,000. Taking into account your rank, home state quota, caste reservation I will list the top colleges for you along with the branch-
  • IIIT Delhi - Indraprastha Institute of Information Technology ( ECE, CS)
  • DTU - Delhi Technological
121 Views

hi sir my name is balaji jee jan 2020 score 96.5141161 percentile my home state Karnataka. I want computer science in engineering in Suratkal nit college please send me answer.

Subhodeep Biswas 9th Feb, 2020
Hey there hope you're doing well.
Dear aspirant, according to your percentile score in JEE MAIN examination your expected rank is about 30,328. Since the cutoff rank for Computer science branch is quite high it's difficult to get CSE at NIT SURATHKAL even with home state quota. You ave not
112 Views

sir can i get admission in betech in computer science in sliet by 81.38 percentile January 2020 jeemains in general category

jishua thomas 9th Feb, 2020

hello aspirant...

for admisssion through the jee mains percentile you need to qualify the exam. that is clear the cutoff for the exam declared. which is not yet declared by the nta but the expected cutoff released says that for the general category it is about 89.75 but your is

145 Views

last year what is cut off rank in computer science betech in punjabi university patiala

Shudhanshu Gupta Student Expert 9th Feb, 2020
Hello.
For your entry in Punjab University Patiala in the course b tech Computer Science and Engineering the cutoff goes near about 300000, but in case of any other quota like SC, BC ,it reaches to 700000,
But some time some of the seats are unoccupied in the Punjab University
164 Views

sir, can i get admission in computer science betech in punjabi university patiala my percentile is 81.38 in jee main January 2020 in general category

Raj Aryan Sharma 9th Feb, 2020

Hi Mannik.

The official cutoff of JEE Mains 2020 will be released along with the final results after the April JEE Mains. The NTA will announce category wise cutoffs then. But you can still check your estimated rank using the formula (100-your total percentile)*869010/100. So with this percentile, your estimated

193 Views

last year cut off rank in computer science betech in punjabi university patiala

Raj Aryan Sharma 9th Feb, 2020

Hi Manik.

The selection in Punjabi University is made on the basis of 12th board percentage and merit in JEE Mains. JEE Mains ranking of under 2.9 lakhs can get you a seat in Punjabi University's Computer Science branch. This cutoff is for general category. For reserved categories like SC/ST,

48 Views

where the choching center of Vijayawada plz tell me about of the choching center in my city of Vijayawada

Leon George 31st Dec, 2019

Hello Beshu,

You haven't mentioned the course for which you are looking coaching centre in your city Vijayawada.

If you are looking for management exam coaching centre in Vijayawada-

  • Royal ED- Serv
  • Inspire Academy
  • Focus 40 Institute
  • V V Academy
  • T.I.M.E

If you are looking for medical coaching centre in

36 Views

which is the best college for computer science.

jishua thomas 30th Dec, 2019

hello deepali thakkar..,

as you know among the colleges of india, the iits stand in top providing the best education, placement, faculty, campus life etc followed by nits. the same is similar in the case for the course of computer science.

there are also few private colleges which keep the

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