Hello Vinay..

According to careers360 rank formula, 

Rank formula= [(100-total score) * (no of students wrote exam)] /100

No of students attended are 874469.

So your expected rank will be nearly around 35,329.

As per previous year jee mains, any rank below 2,00,000 will be qualified for jee advanced.

So

Hello

JEE Main January exam has been conducted and April exam will be conducted from 6 April to 20 April.
Candidates who will appear in both the exams, the best of the two scores will be considered.

It would be difficult to tell you exactly about the marks required as

The exact prediction would be difficult about the qualifying marks or rank & admission possibilities as for the first time JEE Main is being conducted twice by NTA in multiple session.

Based on your NTA percentile score your probable rank will be 249,383 - 279,383 and your probable category rank

Sorry for this..u can't get even low branch in low nits..better luck for ur april exam

Hello aspirant, percentile is a representation of your rank. Your rank is (total number of students -(percentile*0.01*number of students))

Your rank is around 23160. Getting a CSE branch with this rank is tough. You might be able to if you have any quota or try out in NITs not in

Hello Vinay..

According to careers360 rank formula, 

Rank formula= [(100-total score) * (no of students wrote exam)] /100

No of students attended are 874469.

So your expected rank will be nearly around 35,329.

As per previous year jee mains, any rank below 2,00,000 will be qualified for jee advanced.

So

Hello Vinay..

According to careers360 rank formula, 

Rank formula= [(100-total score) * (no of students wrote exam)] /100

No of students attended are 874469.

So your expected rank will be nearly around 35,329.

As per previous year jee mains, any rank below 2,00,000 will be qualified for jee advanced.

So