Hello Rohan.

Hope you are doing well.

As your rank is 46000 you have a very little chance of getting Computer Science seat in Government College. But you can go for Aided colleges. Even they have less fees when compared to the private colleges.

You kindly check this link so

Hi aspirants

yes you can do both at a time . But You are allowed to hold any one Certificate of Practice. So, you will get full recognitions of being a CA (Chartered Accountant) & a CS (Company Secretary) but you cannot practice as both of them.

The advantage is

Hello there, aspirant

These are the best colleges you can get based on your ranking-

• St. Joseph Engineering College - SJEC-B.E. in Computer Science and Engineering
• ATME College of Engineering-B.Tech. in Electrical and Electronics Engineering
• KLS Gogte Institute of Technology-B.E. in Computer Science and Engineering
• SVCE - Sri Venkateshwara College

You are being provided with a link below. Use it to predict the college you can get based on your JEE Mains rank. It is the Careers360 college predictor.
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Hello,

You haven't mentioned your category assuming that you belong to general category here is the previous year cut off for admission to the preferred courses in the above mentioned institutes

B N M Institute of Technology Bangalore

• Computers: 16710
• Info.Science: 18668

Nitte Meenakshi Institutute of Technology Bangalore

• Computers: 8990

Hello aspirant

First of all I m sorry to say this but with this percentile you are not eligible for BNCET Lucknow (cse or it) since from the previous year trends its cut off by rank for 2020 was 70886 and for 70 percentile your predicted rank will be somewhere

Hello Aspirant,

Hope you are doing good. Candidates should have obtained at least 60% marks in aggregate of Physics, Chemistry. and Mathematics and also had English as a subject are eligible to get admitted into NSIT. Since you have 64% in 12th, you are eligible. But mind it, cutoff for